find value of x
2006-08-04 00:38:08 · 19 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
1
2006-08-04 00:40:27 · answer #1 · answered by Anonymous · 0⤊ 1⤋
1=1
2006-08-04 07:40:38 · answer #2 · answered by Auggie 3 · 0⤊ 0⤋
X=69
2006-08-04 07:41:26 · answer #3 · answered by d_oberoi 2 · 0⤊ 0⤋
We know that when we multiply the same variable with different exponents we can add the exponents. For example:
s^6 * s^4 = s^10
So, we have
x^2x^3 = x^3x^2 since 2 + 3 = 5 and 3 + 2 = 5
x^5 = x^5
from this, we see that x = x.
This means that x can be ANY number.
2006-08-04 07:41:05 · answer #4 · answered by polloloco.rb67 4 · 0⤊ 0⤋
although I know that u r not interested by any logical answers
(since your question does not make sense at first glimpse)
I will give a logical answer anyway...
Let's put it this way;
For,
y^2.x^3=y^3.x^2 both x and y must be equal to 1
because we see from the equation that
y^2=y^3 and x^3=x^2 and thus x=y= +1 (not -1)
and same might hold for the equation YOU have written,
it only depends on what u mean by x...
if all the x values are equal then x might be any value....
2006-08-04 07:49:34 · answer #5 · answered by Remzy 4 · 0⤊ 0⤋
x^2x^3 = x^3x^2
x^(2 + 3) = x^(2 + 3)
x^5 = x^5
ANS : Infinite Solutions
2006-08-04 08:42:48 · answer #6 · answered by Sherman81 6 · 0⤊ 0⤋
sorry but thx for 2 pts
btw
whixh of these two do you mean????
x^(2x)^3 = x^8(x^3)
x^2(x^3)
both of these equations does not fit all numbers
2006-08-04 09:16:48 · answer #7 · answered by Croasis 3 · 0⤊ 0⤋
This means x^5 = x^5 which is identity. So it is true for any x
2006-08-04 18:52:17 · answer #8 · answered by Mein Hoon Na 7 · 0⤊ 0⤋
works for any value of x
2006-08-04 07:42:30 · answer #9 · answered by bs 2 · 0⤊ 0⤋
x is anything except and that is very important it can not be 1/0
2006-08-04 07:52:24 · answer #10 · answered by gjmb1960 7 · 0⤊ 0⤋