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2006-08-03 18:10:33 · 7 answers · asked by bhavan k 1 in Science & Mathematics Chemistry

7 answers

I'm thinking that uck stands for kinetic energy. See, E = mc^2 only when the object is at rest. If the object is moving, then E is equal to mc^2/sqrt(1-(u/c)^2), where u is the speed of the object. If the speed of the object is much less than the speed of light, then sqrt(1-(u/c)^2) is equal to 1 + (1/2)* (u/c)^2 by the binomial approximation. In that case E = (1 + (1/2)* (u/c)^2) * mc^2
= mc^2 + (1/2)*mu^2. Notice that (1/2)*mu^2 is just the expression for kinetic energy, which we usually symbolize as K, or uck in your case. So if an object is traveling much slower than the speed of light, then E = mc^2 + K approximately.

or maybe you just want to say Kuck. :)

2006-08-03 18:33:49 · answer #1 · answered by prune 3 · 0 0

e = energy
m = mass
c = speed of light.

It states in this equation that 1 part of mass multiplied by the square of the speed of light (300,000 km/sec), will result to a huge amount of energy.

It also says that mass is just a compacted energy. If you are able to convert say small piece of stone into energy, then it will surely be an enormous amount of energy.

That is why some people think that the atomic bomb was based on this equation. Maybe your asking how spliting of an atoms help release energy. Well studies show that if you are able to split a single atom into two, combining the weights of the first part and second part will produce a much smaller weight as compared to the atomic weight of original whole atom. Therefore energy is released.

However its not easy to convert an object into energy. The best form matter that can be converted into energy is Uranium. Its so unstable that is relatively (although still difficult) easier to split atoms that will release energy.

If you are able to convert 5 pounds of uranium of energy then that is equivalent to 5lbs * 300,000 * 300,000 = 450,000,000,000 lbs km/sec

Imagine exploding 1 ton of uranium. :)

P.S. E=mc2 is not an equation that represents the whole theory of relativity. The theory of relativity is a much deeper concept, and there are still many equations in this concept. E=mc2 is just but one equation in the theory. Ironically its the most famous equation, but only few people understands it.

2006-08-04 01:55:22 · answer #2 · answered by Taki 2 · 0 0

It is the theory of relativity plus a rather arcane and invalidated general magnetic-pseudopotential theory which has been developed for Bloch electrons in a magnetic field. This theory is a generalization of the earlier formulations of Misra and Roth, and Misra, and it includes the effects of spin and spin-orbit interaction. In this method, tight-binding and orthogonalized-plane-wave functions are constructed which have the symmetry of the magnetic Bloch functions and which form a complete set for the wave function of the Hamiltonian of the crystal in a magnetic field. These are used as basis states for the wave function of an eigenstate of the problem, and an effective Hamiltonian is obtained which includes the magnetic pseudopotential. The magnetic pseudopotentials due to Misra and Roth, and Misra, and zero-field pseudopotentials, are obtained from this general magnetic pseudopotential in appropriate limits. The expression for the magnetic pseudopotential has been obtained in a form such that it can be calculated to any order in the magnetic field. This expression is further simplified for metals. The immediate purpose of this formulation is to calculate the total magnetic susceptibility of metals and alloys.

2006-08-04 01:18:28 · answer #3 · answered by mark c 4 · 0 0

Were you going for (ma)+uck?
ma being mass*acceleration = force, or f

Your avatar makes you look like you're screwing around.

2006-08-04 01:18:35 · answer #4 · answered by Phil 5 · 0 0

All this internet language spins my mind, don't know what it means but good luck finding it out.

2006-08-04 01:15:44 · answer #5 · answered by musiccrazy006 3 · 0 0

m=mass
c=speed of light (squared)
u=potential energy
k=kinetic energy

i'm not sure if this is what you were asking for but maybe it helps..

2006-08-04 01:16:35 · answer #6 · answered by just_the_girl 2 · 0 0

It's not internet language aha, it's math... I think at least, IDK I am no good at math

2006-08-04 01:16:37 · answer #7 · answered by toofdogger 3 · 0 0

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