what is the square root of
144x^10y^12z^0
2006-08-03 14:40:31 · 11 answers · asked by bhcky79 3 in Science & Mathematics ➔ Mathematics
12x^5y^6
(x^5)^2 = x^10
(y^6)^2=y^12
Anything to the zero power is 1
2006-08-03 14:50:10 · answer #1 · answered by NONAME 1 · 0⤊ 0⤋
1
2006-08-03 22:12:28 · answer #2 · answered by Cody 3 · 0⤊ 0⤋
144x ^ 10y ^ (12z * 0)
144 x ^ 10y ^ (0)
144 x ^ (10 y * 0)
144 x ^ 0
either 144, or 1, depending on where you have your paranthese
thus, your answer is 12 or 1
2006-08-03 23:04:13 · answer #3 · answered by mommy_mommy_crappypants 4 · 0⤊ 0⤋
sqrt(144 x^10 y^12 z^0)
z^0 = 1, so
= sqrt(144 x^10 y^12)
sqrtx = x^(1/2), so
= (144 x^10 y^12)^(1/2)
(abc)^n = a^n b^n c^n, so
= 144^(1/2) (x^10)^(1/2) (y^12)^(1/2)
Since b^(1/2) = sqrt b and (b^x)^y = b^xy, then
= sqrt(144) x^(10 · 1/2) y^(12 · 1/2)
Since sqrt 144 = ±12 and 10 · 1/2 = 5 and 12 · 1/2 = 6, then
= ±12 x^5 y^6
^_^
2006-08-04 08:09:28 · answer #4 · answered by kevin! 5 · 0⤊ 0⤋
Since square root is quadratic, there are two roots, equal in magniture but opposite in direction. The answers are +12x^5y^6 and -12x^5y^6. (Of course, z^0 is one, assuming z not equals to 0).
2006-08-04 06:32:40 · answer #5 · answered by Anonymous · 0⤊ 0⤋
sqrt(144x^10y^12z^0)
z^0 = 1
sqrt(144) * sqrt(x^10) * sqrt(y^12)
±12 * (x^10)^(1/2) * (y^12)^(1/2)
±12 * x^(10/2) * y^(12/2)
±12x^5y^6
2006-08-04 23:57:31 · answer #6 · answered by Sherman81 6 · 0⤊ 0⤋
as at last you are raising power to `0' the answer is 1.
2006-08-05 06:49:16 · answer #7 · answered by rahul 1 · 0⤊ 0⤋
sqrt(144 x^10 y^12 z^0)
= sqrt(144) sqrt(x^10) sqrt(y^12) sqrt(z^0)
= 12 x^5 y^6
2006-08-03 22:35:20 · answer #8 · answered by ideaquest 7 · 0⤊ 0⤋
12x^5y^6
2006-08-04 09:05:15 · answer #9 · answered by xavierbondoc_15 1 · 0⤊ 0⤋
12x^5y^6
2006-08-04 03:16:27 · answer #10 · answered by Anonymous · 0⤊ 0⤋