16x^9 y^3
2006-08-03 14:34:01
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answer #1
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answered by Mitch 7
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1
2006-08-03 14:34:32
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answer #2
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answered by Kane 2
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a million)y^2 + 8y = 0 y(y+8)=0 Now: y = 0 or y = -8 2) x^2 + 3x -28 = 0 you should finished the sq.: x2 + 3x = 28 Now look on the term in front of the x.. you halve that and sq. it and upload it to the two aspects. (a million/2)*3 = 3/2 (3/2)^2 = 9/4 x^2 + 3x + 9/4 = 112/4 +9/4 Now as you will discover the 9/4 cancels out, meaning we've not replaced the unique equation in any respect! yet we don't cancel out the 9/4 right here. We simplifiy the desirable suited edge: x^2 + 3x + 9/4 = 121/4 Now: x^2+3x+9/4 = (x+3/2)^2 --> by using fact we achieved the sq.: (x+3/2)^2 = 121/4 x+3/2 = sqrt(121/4) x+3/2 = +/- 11/2 x = +/- 11/2 -3/2 So: x = -14/2 = -7 or x = 8/2 = 4
2016-12-14 19:03:45
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answer #3
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answered by ? 2
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I entered your expression into my TI-82, and got the following solution: -.0137646014. And no, I have no idea how it computed this, since you didn't assign values to x or y.
2006-08-03 14:39:18
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answer #4
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answered by ronw 4
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18x+18y
4(4x^3y)+^2(x+^3y)=
16x+12y+2x+6y=
16x+2x=18x
12y+6y=18y
there for 18x+18y is the answer i think
2006-08-03 14:45:37
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answer #5
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answered by Anonymous
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(4x^3y)^2 (x^3y)
(16)(x^6)(y^2)(x^3)(y)
(16)(x^9)(y^3)
2006-08-03 14:34:56
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answer #6
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answered by Michael M 6
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27x3y This is the right answer. I went over it in my math books. Can no one else on Yahoo do math?????!!!!!!
2006-08-03 15:05:34
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answer #7
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answered by Cody 3
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zero -0
2006-08-03 14:34:42
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answer #8
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answered by Anonymous
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(16x^6y^2)(x^3y)
= 16x^9y^3
2006-08-04 01:00:26
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answer #9
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answered by Anonymous
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You can't solve this and you only simplify this.
2006-08-03 14:34:48
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answer #10
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answered by NONAME 1
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