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If you are in a car or a boat and drop a ball in your hand, how fast is the ball going in the horizontal (x) and vertical (y) direction? If you think hard enough and connect it to light, you’ll start rolling down Einstein’s road of relativity.

2006-08-03 12:29:40 · 15 answers · asked by leinervh 5 in Science & Mathematics Physics

15 answers

In the vertical direction, it is under the effects of gravity, the velocity v is:

v = 1/2 g t^2

where t is the time of flight of the ball and g is the gravitational constant, typical g=9.8 m/s^2

In the horizontal direction, it would be take on the velocity of the the car or boat.

2006-08-03 13:34:21 · answer #1 · answered by ideaquest 7 · 1 0

Say you are sitting in the back seat of a car going 60 mph... then you and the ball are going 60 mph (x) supposing you dropped the ball straight down. The ball will be moving at 9.8 metres per second (y) , as it will be pulled to the earth by gravity. I understand what you are trying to say, but I don't quite make the connection to relativity. I think Einstein was wrong... but you ought to clarify what you mean a bit, please.

2006-08-03 19:44:27 · answer #2 · answered by Rat 7 · 1 0

If your in a car or boat that is not moving like your question implies, my answer would be no horizontal speed with tv of the ball vertically for the distance traveled. Be more specific, Albert might be online in another millenium, hmmmm.

2006-08-03 19:35:35 · answer #3 · answered by Cpn Ron 2 · 1 0

HAHA, I like the mondana_8's first answer...

But I'm to lazy to think as hard as you want...

So, since you didn't say the car was moving, I'm assuming I'm just sitting in the car or standing on the boat. Therefore, the ball is moving 0 m/s in the x direction and 9.8 m/s (ideally, not accounting for drag) in the y direction.

2006-08-03 19:36:12 · answer #4 · answered by Dude 3 · 0 1

You are in error. It takes more than connecting it to light to get what Einstein got. One also needs to know that light does not behave like the dropped ball. It's speed is reference independent.

2006-08-03 23:00:00 · answer #5 · answered by 1,1,2,3,3,4, 5,5,6,6,6, 8,8,8,10 6 · 1 0

- u must be specified, am i in a car or in a boat ??

- if u really wanna answer that question then u must give me the velocity of the car (or the boat) ??

- i think light & relativity has nothing to do with this question, its only about velocities in X-axis & Y-axis

- i think its a (projectiles) question more than (hard thinking with light) question

2006-08-04 20:41:20 · answer #6 · answered by Kevin 5 · 1 0

On Y axis it obyes the same gravity but for X axis it will travel corrospondingly with the speed of car or boat.(v=sxt)

2006-08-03 21:40:55 · answer #7 · answered by Ω Nookey™ 7 · 1 0

I'm underwhelmed by your infinite store of generally useless knowledge.

2006-08-04 00:35:22 · answer #8 · answered by Chug-a-Lug 7 · 0 1

What kind of ball?

2006-08-03 19:33:53 · answer #9 · answered by Anonymous · 0 1

there is sn exact physic's formula for that equation. 32 is the # for gravity.

2006-08-03 19:40:41 · answer #10 · answered by mrsscott1215 2 · 0 1

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