How do you solve the following for area and perimeter?

Question

rectangle has a width of 3x +4 cm and length of 2x + 5 cm

Answer 1

6x squared+23x+9cm=area

just use the distribution properety- (3x*2x)+(4*2x)+(5*3x)+4*5


10x+18cm=perimeter
multiply each side by 2 and add:
6x+8+4x+10

Answer 2

Given your info, we're not going to get a number, we'll get an expression that represents the two answers so here goes...

AREA (3x+4)(2x+5) = 6x^2 + 23x + 20 cm^2

PERIMETER 3x+4 + 3x+ 4 + 2x+ 5 + 2x + 5= 10x +18 cm

Answer 3

Perimeter = 2*[3x+4 + 2x + 5] = 2*[5x+9]
= 10x+18

Area= (3x+4)*(2x+5)=6x^2 + 23x + 20

Answer 4

Area: l x w
(3x + 4)(2x + 5) = 6x^2 + 15x + 8x + 20 cm^2

Perimeter: 2l + 2w
2(3x+4) + 2(2x+5) = (6x + 8) + (4x + 10) = 10x + 18 cm

If they give you an x value, you can actually give a real number.

Answer 5

A = (3x + 4)(2x + 5)
A = 6x^2 + 15x + 8x + 20
A = 6x^2 + 23x + 20

P = 2((3x + 4) + (2x + 5))
P = 2(3x + 4 + 2x + 5)
P = 2(5x + 9)
P = 10x + 18

Answer 6

The area formula

A= L x W

A + (2x + 5)(3x + 4)= 6x² + 15x + 8x + 20

A= 6x² + 23x + 20 cm

- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

Perimeter formula

P = 2L + 2 W

P = 2(2x + 5) + 2(3x + 4)

P = 4x + 10+ 6x + 8

P = 10x + 18 cm

Answer 7

just remember for rectangle

Area = Length x Width

Perimeter= 2 x length + 2 x width
----------------------------------------------------

Length= 2x+5
Width = 3x+4
-----------------------------------------------------
So,

Area = Length x Width
= (2x+5) (3x+4)
= 6x² + 8x + 15x +20
= 6x² + 23x +20 cm²

Similarly

Perimeter = 2Length + 2width
=2(2x+5) + 2(3x+4)
= 4x+10 +6x +8
= 10x + 18 cm
--------------------------------------------------------
put value of x which can be 0,1,2,3,4,5..........
and it will satify above equations of perimeter and area