English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

what is the total pressure at a depth of 100m below the surface of a lake. Nothing else is giving (i.e the size or depth of the lake)

2006-08-03 08:39:31 · 4 answers · asked by jonessunrunner1 2 in Science & Mathematics Physics

4 answers

total pressure = atmospheric pressure + (density of the water in the lake*gravity acceleration*depth)

therfore:
P = Pa + d*g*h
since:
all the unknowns r constants
Pa = 1.013*10^5 N/m^2
density of water = 1000 kg/m^2
g = 9.8 m/s^2
& the given is the depth only becouse it is not constant
h = 100 m

therfore:
P = (1.013*10^5) + (1000*9.8*100)
P = 1081300 N/m^2

i hope u got ur point from my explanation

2006-08-03 08:52:06 · answer #1 · answered by Kevin 5 · 0 0

Ptotal = Pfluid + Patmosphere
Pfluid=r*g*h
r=density of fluid
g=acceleration of gravity
h=height of fluid

so Ptotal = Patmosphere + (r*g*h)
Ptotal = (1.01*10^5) + ((1.00*10^3)*9.8*100)
Ptotal = 1.08*10^6

2006-08-03 15:58:04 · answer #2 · answered by Michael 1 · 0 0

multiply 100 times the density of water

2006-08-03 15:50:14 · answer #3 · answered by koki83 4 · 0 0

density of water x meters

2006-08-04 18:38:15 · answer #4 · answered by James 1 · 0 0

fedest.com, questions and answers