Find the y-intercept.?

Question

-x + 3y = 15

(5,0) or
(0, -15) or
(0,5) or
(-15,0)

Answer 1

Plug in 0 for x and you get

(-1)*(0) + 3y = 15

3y = 15

y = 5

so the coordinate will be (x=0,y=5).

Answer 2

The y-intercept of a line is where it crosses the y-axis... meaning the point you're looking for doesn't move left nor right at all... the x-coordinate must be 0.

To find a y-intercept, substitute 0 for x in your equation, and solve for y.

-x + 3y = 15
-(0) + 3y = 15
0 + 3y = 15
3y = 15
3y / 3 = 15 / 3
y = 5.

The y-intercept is 5, and the point at which your line crosses the y-axis is
(0, 5).

Answer 3

to find the y-intercept, set the x-intercept to zero.
0 + 3y = 15; 3y = 15; y = 5.
we said the x-intercept is 0, and now we know the y-intercept is 5. In your answer write the x-intercept first, then the y-intercept, like this: 0,5

Answer 4

in a given standard equation, ax +by=c,c/a is the x-intercept and c/b is the y-intercept.

in the given equation,-x+3y=15,

c/b=15/3=5

since 5 is y and x should be 0, the answer is (0,5).

Answer 5

well since y intercept is when line croses the Y axis then x has to be zero so make it negative, positive or whatever but becomes 0+3y=15 so 3y=15 so y=5.

so the Y intercept is at grid location x=0, y=5

Answer 6

When you have an equation in form ax + by = c, the y-intercept is calculated by c / b

In this case, 15 / 3 = 5.

y-intercepts lie on the y-axis and so have an x-coordinate = 0. Your answer is (0, 5).

Answer 7

-x + 3y = 15
3y = x + 15
y = (1/3)x + 5

ANS : (0,5)