How can I determine the roots of?

Question

Y=(x+4)(x+2)+(x+4)(x-5)
Without sketching its graph?

Answer 1

you have a variable x that you want to determine the value of, and a variable Y that has the value 0. Note that there are two values for x: -4 and 3/2. That's because your problem has two separate x's in it that when multiplied give you an x^2. (x+4)(2x-3) equal x^2 -3x +5x -12, or x^2 +2x -12. A squared x always produces two values for x.

when Y = 0
(x+4)(2x-3)=0
x=-4 and x=3/2

you can graph these results if you wish.

Answer 2

The equation is also :
Y = (x+4) {x+2+x-5}
So
Y = (x+4) (2x-3)
So the roots are for y= 0
that are
x=-4 or
x= 3/2 = 1,5

Answer 3

It is very easy.
Please follow me.
Y=(x+4)(x+2)+(x+4)(x-5)
Or, Y=(x+4) (x+2+x-5)
So, Y= (x+4) (2x-3)
To find out the roots, yhas to be = 0
that is either x=-4 or
x= 3/2 = 1.5

Answer 4

First take (x+4) common and add the remaining terms.
y=(x+4)(2x-3)
=2x*x+5x-12
Using the quadratic equation formula, we can find the roots.

Answer 5

y = (x + 4)(x + 2) + (x + 4)(x - 5)

(x + 4)((x + 2) + (x - 5))
(x + 4)(x + 2 + x - 5)
(x + 4)(2x - 3)

ANS : -4, (3/2)

Answer 6

equate y to 0 and compute.

Answer 7

equate y to 0 and compute.

Answer 8

THis is a quadratic for heavens sake.