Y=(x+4)(x+2)+(x+4)(x-5)
2006-08-02 23:16:33 · 9 answers · asked by mortangle2006 2 in Science & Mathematics ➔ Mathematics
The equation is also :
Y = (x+4) {x+2+x-5}
So
Y = (x+4) (2x-3) = 2x² +5x -12
So the roots are for y= 0
that are
x=-4 or
x= 3/2 = 1,5
The graph is a Parabole that cross y axis at x=-4 and x= 1.5. And the bottom of the parabole is situated where the derivative is equal to 0 The derivative is 4x+5, so it equal to 0 at x=-5/4
So this a parabole whith a minimum at x=-5/4 and that cross y axis at x=-4 and x=3/2
2006-08-02 23:47:33 · answer #1 · answered by fred 055 4 · 0⤊ 0⤋
Replace x with integers like 0, 1, 2, etc. and you will get the corresponding value of Y. This way you will be able to sketch the graph.
2006-08-02 23:34:54 · answer #2 · answered by Suraj 3 · 0⤊ 0⤋
The above eqn can be modified as
Y=4x+5
4x-y+5=0
Slope is 4
& Y intercept is 5
Sketch the graph
Have a good time
Bye
2006-08-02 23:22:48 · answer #3 · answered by vichu_harrypotter 2 · 0⤊ 0⤋
To graph that equation, you may ought to first locate the values of the coordinates. So x may be one. One plus 3 equals to 4, and that 4 is the y-coordinate. then you go over to the graph. go ver horizontally one unit, and then go vertically 4 gadgets. proceed on and advance the line so a techniques as you are able to. by ability of how, you need to connect the criteria with a straightedge.
2016-11-27 23:00:58 · answer #4 · answered by lacy 4 · 0⤊ 0⤋
Simplify the equation and remove the brackets,
make y=0 and compute to find x-intercept,
make x=0 and compute y to find y-intercept (or take the constant)
take coeficient of x squared as slope of the line tangent to the graph,
make a table of x and y for different variables and point the coordinates on the graph.
2006-08-02 23:47:22 · answer #5 · answered by Habesha 1 · 0⤊ 0⤋
there are many methods of doing this but the easiest is to bring the equation into the form y=a((x-h)^2)+k
then a is the depression from the focus, and (h,k) is the turning point
for a more accurate graph substitute a few balues for x
a, h and k are constants
you may want to get a graph plotter from http://freestatistics.altervista.org/math.php
2006-08-02 23:56:19 · answer #6 · answered by mad_sci_123 2 · 0⤊ 0⤋
solve the equation first. (x+4).(x+2) -> x2+6x+8 etc.
You come up with a quadratic equation, easy to sketch.
2006-08-02 23:24:13 · answer #7 · answered by just "JR" 7 · 0⤊ 0⤋
Highlight the text below and hit ctrl-c then go to the website below and click twice in the box and hit ctrl-v enter
(x+4)*(x+2)+(x+4)*(x-5)
http://people.hofstra.edu/staff/steven_r_costenoble/Graf/Graf.html
2006-08-03 06:57:52 · answer #8 · answered by PC Doctor 5 · 1⤊ 0⤋
equate y to 0 and compute.
2006-08-02 23:35:24 · answer #9 · answered by Anonymous · 0⤊ 0⤋