How to sketch(for example)?

Question

(x+3)(x-2)(x-3)
I only knew that roots are 2,3 and -3

Answer 1

As you know the roots so u have got the equation correct i.e (x+3)(x-2)(x-3) which is an equation of degree 3.
Now if u want to sketch it it you have do like following
y=(x+3)(x-2)(x-3)=x^3-2x^2-9x+18

now make a table
------------------------------------------------------------------
x |
------------------------------------------------------------------
y |
------------------------------------------------------------------
put random values in x and get the corresponding values for y and then join these points with a free hand . Be careful that you take values of x which are very close so that graph will be more accurate.

Answer 2

The solution are not strigth lines !!
To determine it take the derivative :
y= xx²-2x²-9x+18
the derivative is
3x²-4x-9
The derivative is equal to 0 at
x1= (4+sqr(124))/6
x2 = (4-sqr(124))/6

So the curves will be like :
x1 //
--------
// x2
//:

between x1 and x2 it is not straigth but I can not represent.

Furthermore this curve has 3 point ((-3,0) (2,0) (3,0))

Answer 3

this is equtio of three straight line passing through 2,3,-3 and parellel to y axis

Answer 4

for a graph, go to http://www.calculator.com/calcs/GCalc.html

type in (x + 3)(x - 2)(x - 3), then click enter on the keyboard

Answer 5

this is a cubic equation and its sketching is included in transformation which is advanced stuff try a graph plotter winplot from
http://freestatistics.altervista.org/math.php

Answer 6

that is math man you would have to sketch an diagram for that man