A slorg creeps 9 ft up a wall during the daytime. After all the labor it does throughout the day, it stops to rest a while... but falls asleep!! The next morning it wakes up and sees that it has slipped down 6 ft while sleeping.
If this happens every day, how many days will the slorg take to reach the top of a wall 39 ft in height?
2006-08-02 14:14:09 · 8 answers · asked by Babygirl 1 in Science & Mathematics ➔ Mathematics
Notice that once the slorg gets up to 30 ft, the next day it will make it up to the top. Every day and night, the slug moves a total of 3 ft upwards. It takes 10 days to move up to 30 ft then one more day to make it to the top.
Thus, it takes 11 days.
2006-08-02 14:17:52 · answer #1 · answered by tedjn 3 · 1⤊ 0⤋
Wait...
Day:Night
9:3
12:6
15:9
18:12
See the pattern? Everyday, the slorg went 3 ft up. so to find the answer, make an equation: 9+3x=39. So subtract 9 on both sides, so 3x=30. then divide by 3 on both sides, so u will get x=10!
To answer your question, it will takes 10 days to reach 39 ft in height!
2006-08-02 22:28:53 · answer #2 · answered by Anonymous · 0⤊ 0⤋
39/(9 - 6) = 39/3 = 13 days
2006-08-03 02:44:10 · answer #3 · answered by Sherman81 6 · 0⤊ 0⤋
13 days
2006-08-02 21:18:07 · answer #4 · answered by Ace 3 · 0⤊ 0⤋
13 days?
2006-08-02 21:17:29 · answer #5 · answered by El Duderino 6 · 0⤊ 0⤋
11 days.
2006-08-02 21:19:03 · answer #6 · answered by cotopaxi 5 · 0⤊ 0⤋
11 days.
2006-08-02 21:17:00 · answer #7 · answered by Vincent G 7 · 0⤊ 0⤋
As many times as it takes.
2006-08-02 21:16:39 · answer #8 · answered by Anonymous · 0⤊ 0⤋