2006-08-02 12:42:56 · 6 answers · asked by aargre 2 in Science & Mathematics ➔ Mathematics
Using point-point form, an equation of the line containing the two points is
y-y_1=(y_2-y_1)/(x_2-x_1)*
(x-x_1)
Setting x=0 gives us
y-y_1=(y_2-y_1)/(x_2-x_1)*
(0-x_1)
y=-x_1(y_2-y_1)/(x_2-x_1)+y_1.
Thus, the y-intercept is
(0, -x_1(y_2-y_1)/(x_2-x_1)+y_1)
2006-08-02 14:00:57 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Find the slope (y2-y1)/(x2-x1) which is m.
Then use the point slope formula where you substitute m and (x1, y1)...y-y1=m(x-x1) Don't substitute anything for the plain x and y. Distribute the m then add y1 to each side of the equation and you now have the equation is y-intercept form which is y = mx+b and b is your y-intercept.
2006-08-02 20:05:08 · answer #2 · answered by MollyMAM 6 · 0⤊ 0⤋
First find the slope : (y2 - y1)/(x2 - x1) Let's call this m.
then the y-intercept of line will be y1 - m*x1 (or y2 - m*x1)
2006-08-02 19:48:38 · answer #3 · answered by Bernice 2 · 0⤊ 0⤋
use the formula for straight line: y=mx + b where m is the slope and b is the Y intercept
the included link can give you more details.
2006-08-02 19:51:14 · answer #4 · answered by blah_in_az 2 · 0⤊ 0⤋
the answer has to be 0
2006-08-02 19:50:34 · answer #5 · answered by ken o 2 · 0⤊ 1⤋
(x1,y1), m = (y2 - y1)/(x2 - x1)
y1 = ((y2 - y1)/(x2 - x1))(x1) + b
b = y1 - (((y2 - y1)/(x2 - x1))(x1))
or
b = (((x2 - x1)(y1)) - ((y2 - y1)(x1)))/(x2 - x1)
2006-08-02 21:06:13 · answer #6 · answered by Sherman81 6 · 0⤊ 0⤋