Need more accuracy ?
I have that problem a lot.
If
x = 985214536325442539855478563215448112914542543455
and
y = SqRt(x)
then
y = 992579738018786347548394.9665116169373920487350941038112391917958762061884621188
approximately.
Check:
y² = 985214536325442539855478563215448112914542543454.99999999999999999999999999999997
Rounding to nearest integer:
y² = 985214536325442539855478563215448112914542543455 = The original value.
NOTE:
For some reason, the decimal parts of several numeric values in my post are being cut off!
If you are using Internet Explorer, putting the pointer over the number may display the entire value as tool tip text.
2006-08-02 13:03:45
·
answer #1
·
answered by Jay T 3
·
2⤊
0⤋
Try the calculator built into Windows. It can handle many more digits than a TI calculator.
Oops. It won't take 48 digits. Maybe try Maple or Mathematica in the computer lab at school.
2006-08-02 21:01:38
·
answer #2
·
answered by IPuttLikeSergio 4
·
0⤊
0⤋
It's too many digits for many things. What you could do, though, is an approximation. It'll be between 4.303655845x10^14 and 4.303655846x10^14, but closer to the former.
2006-08-02 19:35:06
·
answer #3
·
answered by DakkonA 3
·
0⤊
0⤋
992,579,738,018,
786,347,548,394
plus some decimal.
Yahoo doesn't want to print out all the digits for me, either!
By the way, your full number is nearly 10^48. Therefore, your answer should be close to 10^24, like the one above.
2006-08-02 19:39:47
·
answer #4
·
answered by Polymath 5
·
0⤊
0⤋
3.139912731times 10^12--this is engineering notation, in regular numbers, it is 3,139,912,731,000. I'm using a TI-82
2006-08-02 19:37:05
·
answer #5
·
answered by ronw 4
·
0⤊
0⤋
Try working it in Excel.
2006-08-02 19:29:32
·
answer #6
·
answered by normy in garden city 6
·
0⤊
0⤋
it's aproximently 3.138812731x10^14.
2006-08-02 19:58:36
·
answer #7
·
answered by vampbookworm 3
·
0⤊
0⤋