A golfer hits a tee shot on a 350m long straight fairway. The ball is sliced (hit at an angle) at 21 degrees to the right. The ball lands 210 m away from the tee. How far is the ball from the hole.
2006-08-02 10:22:54 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Let b = 350m.
Let c = 210m.
Let A = 21°.
You're looking for distance a.
The Law of Sines is not very helpful with this problem, because you don't have measurements for any side and opposite angle pair. Use the Law of Cosines.
Law of Cosines:
a² = b² + c² - 2bc·cos(A)
a² = 350² + 210² - 2(350)(210)cos(21°)
a² = 122500 + 44100 - 147000(0.93358)
a² = 166600 - 137236.322695
a² = 29363.6773
a = √29363.6773
a = 171.35833 meters
2006-08-02 12:49:54 · answer #1 · answered by Anonymous · 0⤊ 0⤋
If you disregard angle that it is sliced at you can set up a simple 3,4,5 right triangle. the missing side would be 280.
3^2+4^2=5^2
70*3=210
70*4=280
70*5=350
210^2+280^2=350^2
It might work using the law of sines ,but that seemed like a lot of work.
If you need it the law of sines:
A/sin(a)=B/sin(b)=C/sine(c)
Capital letter equals side opposite angle labeled with the same letter.
2006-08-02 11:08:05 · answer #2 · answered by shin 1 · 0⤊ 0⤋
the ball is hit to the right of the tee
210*sin(21) = 75.26 m and 210*cos(21) = 196.05 m straight ahead of the tee....So there is 350 - 196.05 = 153.95 m still left to go to the hole..... 153.95^2 + 75.26^2 = c^2 is 171.36 m from the hole
2006-08-02 10:35:44 · answer #3 · answered by mdc 2 · 0⤊ 0⤋
What country was this in? Do you know any place where fairways are measured in meters instead of yards?
2006-08-02 10:47:34 · answer #4 · answered by bpiguy 7 · 0⤊ 0⤋