2 > 8-3x > 1/2
2 > 8-3x and 8-3x > 1/2
3x > 8-2 and 8-1/2 > 3x
3x > 6 and 15/2 > 3x
x > 2 and 7.5/3 > x
x > 2 and 2.5 > x
So,
2 < x < 2.5
In interval notation: (2; 2.5)
Easy eh? 10 points please!
2006-08-02 10:14:18
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answer #1
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answered by Anonymous
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(x+5)(x-5)<=0 x+5=0 x=-5 x-5=0 x=5 you create a signum table x -5 5 x+5 - - - - 0 ++++++ x-5 - - - - - - - - - - - - - 0 +++++ (x+5)(x-5) + + +0 - - - -0 +++ the inequality would desire to be much less or equivalent to 0 so which you will pick the parte of the table the place the inequality is adverse , So x is between -5;5
2016-10-01 09:52:09
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answer #2
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answered by rafael 4
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4>16-6x>1 (get rid of fraction)
-12>-6x>-15 (subtract 16)
2
(2, 15/6)
Interval notation like you requested.
2006-08-02 10:16:37
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answer #3
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answered by Anonymous
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2 < x < 2.5
2006-08-02 10:43:41
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answer #4
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answered by amira 1
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2 > 8 - 3x > (1/2)
-6 > -3x > (1/2) - 8
-6 > -3x > (1/2) - (16/2)
-6 > -3x > (-15/2)
2 > x > 2.5
(2,2.5)
2006-08-02 10:55:05
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answer #5
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answered by Sherman81 6
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I would help do your hw, but I really stink at math...sorry
2006-08-02 10:15:19
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answer #6
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answered by < Roger That > 5
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U are a NERD
2006-08-02 10:15:28
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answer #7
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answered by PR 4
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