A Kite has a string...?

Question

A Kit has a stiring of 180m long and is helf 2 m above the ground.The strings makes an angle of 41 degress with the ground.
Determine the height of the kite.

Answer 1

I'm assuming you are talking about a geometry problem where the string forms a perfectly straight line and thus you can draw a picture of a right triangle. (In reality, the string forms a catenary, like the cable of a suspension bridge, because the weight of the string has an effect. Leaving that out, we'll assume it is a straight line.)

If the kite was held on the ground, then it would be 180 * sin(41°).
But since it is 2m above the ground, it would be that plus 2.

Think of the shape it forms as a right triangle. Remember the SOH-CAH-TOA mnemonic. Here you know the hypotenuse (h = 180) and the angle (41°). You want the side opposite (o) the angle.

SOH means sin(angle) = o/h.
Rewritten o = h * sin(angle)

sin(41°) = 0.656059...
180 * sin(41°) = 118.09...
So the opposite leg of the triangle is 118.09m

Add the additional 2 meters that the string is above the ground:
180 * sin(41) + 2 = 120.09m

The answer is 120.09m

Answer 2

Height = (180 + 2 )Sin 41°.
Height = (182)(0∙656059029)
Height = 119∙4027433

Answer 3

assuming weightless string, then the string will be straight (a line, not a curb).

this gives us a height of 2+180*sin(41) meters

ask your calculator to do the maths.

Answer 4

The string would form what is called a "modified" catenary curve. You need the weight of the string and force of the kite.

Answer 5

sin(41) = (opposite)/180
sin(41) = x/180
x = 180sin(41)
x = about 118 meters

now add 2

The kite is about 120 meters off the ground.

Answer 6

height of kite from ground=2+180sin41
=2+180x.66
= 2+118.8
= 120.8 meter

Answer 7

180 tan(41) + 2.

Answer 8

It's NOT 180*tan(41) + 2

It's 180*sin(41) + 2.....

Answer 9

120.09m