2006-08-02 07:22:21 · 12 answers · asked by Jalisa G 1 in Science & Mathematics ➔ Mathematics
The question should read as
Solve xy - 3x -8y + 24 = 0
which is equivalent to
(x-8)(y-3)=0
For a product of 2 numbers to be 0, one of them (or both) has to be 0. So the answer is:
x = 8 OR y = 3
OR is important here.
2006-08-02 07:54:46 · answer #1 · answered by Stanyan 3 · 0⤊ 0⤋
xy - 3x - 8y + 24?
=x(y-3)-8(y-3)
=(x-8)(y-3) a quadratic equation having two variables. If the expression becomes zero, then x=8 & y=3.
2006-08-02 08:02:05 · answer #2 · answered by sharanan 2 · 0⤊ 0⤋
the answer is: xy - 3x - 8y + 24
2006-08-02 07:41:15 · answer #3 · answered by Bella 2 · 0⤊ 0⤋
If (x -8) (y -3) = 0
The graphically, the solution is a line through X=8 to infinity and a line through y=3 to infinity. The lines intersect at X=8 and Y=3.
2006-08-02 08:04:31 · answer #4 · answered by oldbutcrafty 2 · 0⤊ 0⤋
xy - 3x - 8y + 24
xy - 8y - 3x + 24
(xy - 8y) + (-3x + 24)
y(x - 8) - 3(x - 8)
(y - 3)(x - 8)
2006-08-02 09:28:04 · answer #5 · answered by Sherman81 6 · 0⤊ 0⤋
(8-x)(3-y) = xy - 3x - 8y + 24
unless you mean:
(8-x)(3-y)=0,
then either:
1) x = 8, y = RANDOM
2) y = 3, x = RANDOM
2006-08-02 07:35:49 · answer #6 · answered by Anonymous · 0⤊ 0⤋
1 equation in 2 unknowns
u need another equation or assume one of the variables and get the other
unless u're using numerical analysis which is a b***** and i cant help u with that
2006-08-02 08:27:43 · answer #7 · answered by la_fille_en_blue 2 · 0⤊ 0⤋
Factors to: (x-8)(y-3)=0
x=8 or y=3
2006-08-02 07:29:53 · answer #8 · answered by Anonymous · 0⤊ 0⤋
y = 3
x = 8
If you left off the fact that the equation is equal to zero. Otherwise, ignore my answer.
2006-08-02 07:29:25 · answer #9 · answered by vliam 3 · 0⤊ 0⤋
this isn't solvable
2006-08-02 07:28:07 · answer #10 · answered by gamer girl 2 · 0⤊ 0⤋