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PLZ explain how to do these problems

4x2- 2x2 + (-8x2)


Note those bigs twos are to the second power...

Multiply monomials

x3 x 3x5


again those are to the 3rd and 5th power

raise the following to their powers

(2x5)7

5 nd 7 are small


DIVIDING monomials

12x'2
--------
3x'4


PLEASE EXPLAIN HOW TO DO THISSSSSSSs

2006-08-02 04:02:25 · 6 answers · asked by joe c 2 in Science & Mathematics Mathematics

6 answers

Klo-Jann:
4x2- 2x2 + (-8x2)
=x2(4 - 2 - 8)
= -6x2
You can factorize it as above and solve for the problem.
Klo-Mann:
Multiply monomials
x3 * 3x5
=3x(3+5)
=3x8
Apply the laws of indices to this problem.
Klo-Jann:
raise the following to their powers
(2x5)7 (5 and 7 are small--exponent)
=2x(5*7) (*=times)
=2x35
Apply the laws of indices to this problem.
Klo-Mann:
DIVIDING monomials
12x'2
--------
3x'4
Simplify it:
12x'2 / 3x'4
=4 / x'2
This time, refer to source A.

2006-08-02 04:14:16 · answer #1 · answered by Adrienne 6 · 0 0

1. you can only add or substract the cooeficient if the 'x' has the same 'power'...
ex: 5x^3 + 2x^2 + 3x^2 = 5x^3 + 5x^2

2. if you multiply, add the 'power'. if you divide, substract the power.
(x^3)*(x^1) = x^(3+1) = x^4
(x^3)/(x^1) = x^(3-1) = x^2

3. if you raise a number with power to a certain power, mulitiply it...
(x^3)^2 = X^(3*2) = x^6


SO,
1. 4x^2 - 2x^2 - 8x^2 = -6x^2
2. x^3 * 3x^5 = 3x^8
3. (2x^5)^7 = 2x^35
4. 12x^2 / 3x^4 = 4x^1/2

2006-08-02 11:15:26 · answer #2 · answered by Imoet 2 · 0 0

4x^2 - 2x^2 - 8x^2
(4 - 2 - 8)x^2
(2 - 8)x^2
-6x^2

--------------------------

x^3 * 3x^5
3 * x^(3 + 5)
3x^8

---------------------------------

raise the following to their powers

(2x5)7

(2x^5)^7
(2^7) * x^(5 * 7)
128x^35

----------------------------------

12x'2
--------
3x'4

(12x^2)/(3x^4)
(12/3) * x^(2 - 4)
4x^-2
4/(x^2)

2006-08-02 11:54:47 · answer #3 · answered by Sherman81 6 · 0 0

You lost me at please.

???

Nice to have others do your schoolwork. There was no Yahoo! Answers for me. I did it all myself. You are never gonna learn.

2006-08-02 11:27:24 · answer #4 · answered by nursie 3 · 0 0

umm..try doing your own homework

2006-08-02 11:06:43 · answer #5 · answered by TP 4 · 0 0

You lost me. I'm thinking, I'm thinking...
I pick uh... (c)

2006-08-02 11:08:42 · answer #6 · answered by Anonymous · 0 0

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