Given f(x) = 5x^2 - 3x +1, find f(-2).?

Answer 1

f( x) = 5x² - 3x + 1

f(- 2) = 5( -2)² - 3( -2) + 1

5(4) - (-6 ) + 1

20 + 6 + 1

27

The answer is 27

Answer 2

20 +6 + 1 = 27

Answer 3

5(-2)^2 - 3(-2) + 1 = 5(4) + 6 + 1 = 20 + 7 = 27

Answer 4

f(-2)=5*(4)+6+1=20+6+1 = 27

Answer 5

f(x)= 5(-2)^2-3(-2)+1
= 5(4)+6+1
=27

Answer 6

27

Answer 7

27

Answer 8

i wager you're searching to element 6x² – 3x – a million making use of in easy words Integers. it truly isn't any longer attainable. Why you ask. the aspects of the polynomial are used to sparkling up 6x² – 3x – a million = 0. If ok is a answer to this equation, then x – ok is a element of the polynomial. to locate the recommendations to the quadratic equation use the quadratic formulation. for the classic quadratic equation ax² + bx + c = 0, the recommendations are [-b + ?(b² ? 4ac)]/(2a) or x = [-b ? ?(b² ? 4ac)]/(2a). The huge style lower than the unconventional, b² ? 4ac is the “discriminant.” a million. If b² ? 4ac = 0, then there is in easy words one answer (-b/2a) talked about as a “double” root 2. If b² ? 4ac >0 and a acceptable sq., then there are 2 Rational roots 3. If b² ? 4ac > 0 yet no longer a acceptable sq., then there are 2 Irrational roots 4. If b² ? 4ac < 0, then both roots are complicated conjugates (m + ni)(m – ni) To element a quadratic trinomial ax² + bx + c, compute the discriminant. If that value is a acceptable sq., then the trinomial has rational binomial aspects, otherwise no longer. on your exercising a = 6, b = -3 and c = -a million. The discriminant is (-3)²? 4(6)(-a million) = 33 yet 33 isn't a acceptable sq., so the recommendations are irrational numbers. in certain [3 + ?33]/12 and [3 ? ?33]/12 So the aspects of the polynomial are (x ? [3 + ?33]/12)(x ? [3 ? ?33]/12)

Answer 9

(5x)^2-3x+1 or 5(x^2)-3x+1
In the first case, its 107. In the second, its 27.

Answer 10

f(-2)=5(-2)^2-3(-2)+1=27