log25 in the base 9
or
log9 in the base 4
please write me the solution too.
best regards,
Mehrazin
2006-08-01 20:45:31 · 5 answers · asked by mehrazin 1 in Science & Mathematics ➔ Mathematics
If we don't know the amount of log25 or log9 how we can solve this problem??
2006-08-02 04:29:57 · update #1
log(25) base 9 is defined by x such that 9^x=25
log(9) base 4 is defined by y such that 4^y=9
Take any logs (base 10, e.g.) of those equations to get:
x=log(25)/log(9); y=log((9)/log(4)
x=1.465; y=1.585 so log(9) base 4 is larger.
2006-08-01 21:14:07 · answer #1 · answered by gp4rts 7 · 0⤊ 0⤋
log25 to the base 9 = x
Then 25=9^x
log 25 = x log 9 (log to a common base)
x = log 25 / log 9 = 1.465
similarly
y = log 9 / log 4 = 1.585
Therefore log 9 in base four is larger
2006-08-02 04:53:57 · answer #2 · answered by blind_chameleon 5 · 0⤊ 0⤋
log 25 base 9=log 5 base 3=(log5)/(log3) {base can be any thing}
=(.699)/(.4771)
=1.465101 [approx.]
similarly log 9 base 4=(log3)/(log2)
=(.4771)/(.301)
=1.585049 [approx.]
so clearly log 9 bse 4 is bigger
2006-08-02 05:21:33 · answer #3 · answered by mathe_hari 1 · 0⤊ 0⤋
yeah definatly 12
2006-08-02 03:50:43 · answer #4 · answered by Anonymous · 0⤊ 0⤋
what on earth does log and base mean???>?
2006-08-02 04:39:27 · answer #5 · answered by Blah 2 · 0⤊ 0⤋