2006-08-01 16:17:24 · 7 answers · asked by sandraross1956 1 in Education & Reference ➔ Homework Help
l=3w-2
2(l)+2(w)=44
2(3w-2)+2w=44
6w-4+2w=44
8w-4=44
8w=48
w=6
l=3(6)-2
l=18-2
l=16
2006-08-01 16:26:20 · answer #1 · answered by hfmgr06 4 · 0⤊ 0⤋
X=length of the garden
Y=width of the garden
P=44 =Perimeter of the garden
X=3Y-2
44=2X+2Y so we can say 44=2(3Y-2)+2Y
& 44=8Y-4 & Y=6 then X=3*6-2 so X=16
2006-08-01 16:35:00 · answer #2 · answered by Sam 1 · 0⤊ 0⤋
Simultaneous equations and word problems! Fun!
There are two equations and two unknowns.
L is length W is width
Eqs.
L = 3W-2
44ft = 2L + 2W (perimeter)
Solve for one unknown and plug into other Eq.
Using perimeter Eq and solving for L
(subtract 2w from both sides)
44 - 2W = 2L
Divide both sides by two
22 - W = L
Plug 22 - W into first Eq for L
22 - W = 3W - 2
Add W to both sides of the Eq
22 = 4W -2
Add 2 to both sides
24 = 4W
Divide both sides by 4 to solve for W
6ft = W
Use first Eq to solve for L
L = 3(6) -2
L = 16ft
Check by plugging into second equation
44ft = 2(16) + 2(6) = 32 + 12 =44 CHECKS!
2006-08-01 16:34:12 · answer #3 · answered by hack_ace 4 · 0⤊ 0⤋
You didn't complete the question but...
Let the width be W, then Length can be expressed as 3W-2
The perimeter is (W + 3W -2) * 2
The formula is 44 = (W + 3W - 2) * 2
22 = 4W - 2
24 = 4W
W = 6
L = 3(6) - 2
L = 16
2006-08-01 16:27:25 · answer #4 · answered by tkquestion 7 · 0⤊ 0⤋
There are two variables: w, l. l=3w-2.
According to problem the parameter is equal to 44 ft.
General equation:
P=2w(width)+2l(length)
As we already know P(parameter)=44
44=2w+2(3w-2)
44=2w+6w-4
44=8w-4
44+4=8w
48=8w
6=w
l=3w-2
l=3*6-2
l=16
2006-08-01 20:07:44 · answer #5 · answered by Lin 1 · 0⤊ 0⤋
the sum of the length and width is 22, so x+3x-2=22
4x=24
x=6
its a 16x6 garden, the length being 16 and the width being 6
2006-08-01 16:23:56 · answer #6 · answered by kay 2 · 0⤊ 0⤋
Go with the answer from hfmgr06, it shows all the steps.
2006-08-01 16:44:21 · answer #7 · answered by springday 4 · 0⤊ 0⤋