Solve: 2x+3y=11 3x-2y= -3?

Question

This is a math problem I am having a hard time with, it is listed as follows:
Solve:
2x+3y=11
3x-2y= -3

Answer 1

Solve,

2x + 3y = 11 ... (1)

3x - 2y = -3 ... (2)

Multiply (1) by 3,

6x + 9y = 33 ... (3)

Multiply (2) by 2,

6x - 4y = -6 ... (4)

Now, (3) - (4),
9y - (-4y) = 33 - (-6)

13y = 39

y = 3

Substitute y = 3 into (1)

2x + 3(3) = 11

2x = 11 - 9

x = 1

Therefore x =1 and y =3

Answer 2

x=1 and y=3

Answer 3

This simple we need to solve by elimination

multiply 1st by 2 and 2nd by 3(we have to make coefficient of one variable may be with a sign difference same) in this case y
4x+6y = 22
9x -6y = -9
add the two 13x = 13 or x =1

put in 1st equation
2+3y = 11 or 3y = 9 so y =3
so x =1 y = 3

Answer 4

x=1
y=3

multiply both sides of the first equation by 2
multiply both sides of the second by 3
then

4x + 6y = 22
9x - 6y = -9
add both together.
13 x = 13
x = 1
substitute x=1 into either equation to find y = 3

Answer 5

x=1
y=3

multiply both sides of the first equation by 2
multiply both sides of the second by 3
then

4x + 6y = 22
9x - 6y = -9
add both together.
13 x = 13
x = 1
substitute x=1 into either equation to find y = 3

Answer 6

2x + 3y = 11
3x - 2y = -3

Multiply top by 2 and bottom by 3

4x + 6y = 22
9x - 6y = -9

13x = 13
x = 1

3x - 2y = -3
3(1) - 2y = -3
3 - 2y = -3
-2y = -6
y = 3

ANS : (1,3)

Answer 7

multiply the two eqn a million by 3 and eqn 2 by 2 we get 6x-9y=-33 ------3 6x+4y=fifty 8 -------4 subtracting 4 from 3 you get -13y=-ninety one therfore y=7 replace this value of y in eqn a million or 2 or 3 or 4 we could say eqn a million you get 6x-sixty 3=-33 therfore x=5 desire this facilitates

Answer 8

2x+3y=11
Or, 6x+9y=33...........eq1

And 3x-2y= -3
Or, 6x-4y=-6.......eq2
Subtract Eq2 from eq1 and we get
13y=39. So, y=3.
And putting the value of y in the first equation2x+3y=11, we get
x=1.

Answer 9

Scott R has the correct answer.

x = 1
y = 3

Answer 10

E=MC squared.