line that has a y-intercept of 2 and a x-intercept of 5?

Answer 1

y = (-2/5)x + 2

Answer 2

the reqd eqn is 2x + 5y = 10

i assumed that you need the eqn of the line with the above parameters.

to simplify the solution lets go by the simple formula of co-ordinate geometry

eqn of line ==> x/a + y/b = 1 .... ( a = x intercept and b = y intercept)
by substituting a as 5 and b as 2 we get
==> x / 5 + y / 2 = 1
or 2x / 10 + 5y / 10 = 1
or, 2x + 5y = 10

Answer 3

start with formula for a straight line

y=mx+b

the y intercept, is that place where x=0, and in this case y=2
the x intercept, is that place where y=0, and in this case x=5

you have 2 points for the line to go through (0,2) and (5,0)

plug in values of x=0, and y=2 and solve for "b" [or you could just remember that "b" is the y intercept in this form of the equation
y=m*(0)+2
y=2

so, our equation is y=mx+2 and we can plug in the other pair and solve for "m"

(0)=m*5+2
-2=5m
-2/5=m\

then y=-2/5x+2

voila!

Answer 4

if there is x intecept, that mean, one point is (5,0)
if there is y intercept, that mean,2nd point is (0,2)

Now we have two points (5,0) and (0,2) and we can easily find equation by:

(Y-Y1)/(Y2-Y1) = (X-X1)/(X2-X1)

for it (X1,Y1) is (5,0)
(X2,Y2) is (0,2)

put it and get the answer.

(Y-0)/(2-0) = (X-5)/(0-5)
Y/2 =(X-5)/(-5)

-5(Y) =2(X-5)
-5Y=2X-10

2X+5Y-10=0 is equation of your question =)

Answer 5

you dont have a slope so how am i suppose to answer the question