The line that has a slope of -4 and passes throughthe point (2,3)?

Answer 1

Point-Slope Form of a Line:
y - y1 = m(x - x1),
where (x1, y1) is a given point, and m is the slope.

Your point is (2, 3), so x1 = 2, y1 = 3. The slope, m = -4. Substitute these values into your formula:

y - 3 = -4(x - 2)

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If that's good enough, you're done. If you're supposed to manipulate the equation to another form of a line, it just takes a little algebra.

y - 3 = -4(x - 2). [Distribute.]
y - 3 = -4x + 8.

If you need your answer in Standard Form
(Ax + By = C), add (4x + 3) to both sides:
4x + y = 11.

If you need your answer in Slope-Intercept Form
(y = mx + b), add 3 to both sides:
y = -4x + 11.

Answer 2

y = -4x+b. We need to find b, but we know that when x = 2, y =3. Therefore we write 3 = -4*2+b or 3=-8+b. Therefore b = 11.

The line with slope -4 that passes through (2,3) is y = -4x+11.

Answer 3

the equation of the line is y=-4x+11
-4 is the slope and 2 is the x
when you multiply you would have 3=-8+b
you would solve for b by adding 8 to 3 which will give you 11

Answer 4

the reqd eqn is 4x + y - 11 = 0

solution
it is given that slope (m) = -4 and point (x, y) = (2, 3)
by using the point slope form equation which is y = mx + c we can find c

3 = -4*2 + c
c = 8 + 3 => 11

now by sub. c = 11 and m = -4 to find the eqn we get
y = -4x + 11
or 4x + y - 11 = 0

Answer 5

On this one, use the point-slope equation:

y - y1 = m(x - x1)

where m is the slope and (x1 , y1) is a point on the line.

y - 3 = -4(x - 2)
y = -4x + 8 + 3
y = -4x + 11
y + 4x = 11

Answer 6

formula for slope is m=(y2-y1)/(x2-x1)

where x1,y1 is one coordiation and x2,y2 is another coordinate

put slope m=- 4
x1 and y1 as point (2,3)

simplfiy it. that is.

(Note: u may write x2 as x and y2 as y to make it simplied).

by putting -4=(y-3)/(x-2)
-4(x-2)=(y-3)
-4x+8=y-3
-4x-y+11=0
or 4x+y-11=0 is the equation of the line u mentioned