2006-08-01 10:56:49 · 7 answers · asked by T R 1 in Travel ➔ United States ➔ Orlando
either at universal studios or on their website.
2006-08-01 11:00:33 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Hi Guy
I go to Florida all the time. There are a number of discount ticket places my fave (and not a time share by way )is on HWY 192 at the big orange its really easy to find take the celebration exit past old town about 1/2 a mile on the left I get Busch gardens Universal and everything but Disney ( who doesnt do discounts ) if you want multiple day deals the best deals are on the same road about another 3/4 miles on the right is a Walmart with a travel agency in it I bought enough in there about 3 years ago to keep me in tickets for the next 3 years also try ebay most of the time its not that great a idea because people bid stupidly ( more than gate price sometimes) but sometimes you get lucky Have Fun!
2006-08-01 23:45:30 · answer #2 · answered by magicboi37 4 · 0⤊ 0⤋
Right now, if you go to the Universal studios website you can get 2 day/2 park ticket for 100 dollars. Then they let you use it for an additional 3 days so you're paying for 5 days at the price of a 2day discount. You can also select to add on a free child ticket. This special ticket also allows you access to City Walk which is where all the nice restaurants and clubs are!
2006-08-02 12:59:01 · answer #3 · answered by duchessamber 2 · 0⤊ 0⤋
This place I tell people to go to. I live in central Florida & buy my dinner show tickets here (I have a season pass to Universal). The office is located across the street from "medevil Knights dinner show". The store is also a gift shop.
2006-08-01 20:23:39 · answer #4 · answered by Xtal 4 · 0⤊ 0⤋
either Universal Studios website, or if you are a member of AAA, they usually have a good deal.
2006-08-02 07:32:06 · answer #5 · answered by tweetymay 6 · 0⤊ 0⤋
Universal's website or AAA
2006-08-05 22:16:23 · answer #6 · answered by Shanan D 4 · 0⤊ 0⤋
if your have AAA.
2006-08-07 18:32:35 · answer #7 · answered by elaine p 3 · 0⤊ 0⤋