Help in physics.Please?

Question

What is the linear speed due to the Earth's rotation of a point at the following locations?
(a) on the Equator (REarth = 6.38 * 10^6 m)?
m/s
(b) on the Arctic Circle (latitude 66.5° N)?
m/s
(c) at a latitude of 34.0°N?
m/s

Answer 1

v=rw where v is speed, r is the radius, and w is angular velocity.

Angular velocity describes how fast a circular (or spherical) object is rotating. It has to be in radians per second. There's 2 pi radians in the circumference of the equator. It takes about 24 hours, or 86,400 seconds for the Earth to rotate once. A good estimate for angular velocity is (2 pi)/86400, or 7.27 x 10^-5 rad/sec. (A more accurate number would be 7.292115 x 10^-5 rad/sec; it's a WGS-84 constant).

A good estimate for the radius of the Earth at the equator is 6.38 x 10^6 m (a more accurate number would be 6,378,137 m; another WGS-84 constant).

You multiply 6.38x10^6 by 7.27x10^-5 to get 46.4 x 10^1 meters/sec, or 464 m/sec.

Everywhere other than the equator, you need the distance from the Earth's rotational axis instead of the distance from the center of the Earth. To find that, multiply the equatorial radius by the cosine of the latitude.

For example, the radius at 66.5 deg would be 6.38x10^6 * cos 66.6 deg, or 2.54x10^6 meters. The new radius would use the same equation, v=rw.

However, if you look at the equation, there's a shortcut.

The new radius is r cos 66.5, so:
v=r cos 66.5 w
v=rw cos 66.5
v=464 m/s cos 66.5

Having found the speed at the equator, just multiply that speed by the cosine of the latitude for the other points you need.

Answer 2

Well you know the speed of the earth's rotation, that's good. Now imagine the axis on which the earth spins. Draw a right triangle, one vertex at the center of the earth, one at the point on the earth at the specified latitude, and the last vertex at the axis of rotation... it's just a trig problem that also uses S = r*theta

Answer 3

Linear velocity for a point moving in a circular arc is:

angular velocity times the radius (r) from the center.


So to find out what a persons speed is at different points on earth, you need to know the persons distance from the vertical line that runs from the north pole to the south pole, then multiply that by 6.28319/86400= 0.000073 revolutions per second

I got the 6.28319 by knowing that one revolution is two pie radians or 2 times 3.14159 .

i got 86400 from knowing that the earth takes 24 hours to complete one revolution, and there is sixty minutes to an hour, and 60 seconds to a minute.

Answer 4

in simple terms greater advantageous physics jargon ... i'm not even helpful if it rather is nice anymore ... Photons and gluons are strictly massless. they are the gauge fields of unbroken symmetries (in assessment to the susceptible vector bosons). by using using stable rigidity and the self-interactions of the gluons (the stable rigidity originates from a non-Abelian team -- so there is self interaction between the gauge fields -- the gauge fields themselves are charged), there can be gluon condensation and the condensation looks extensive. As they are massless, they don't immediately paintings which includes Higgs boson on the tree-element. At larger-loop ranges, there are interactions pondering the reality which you have gotten all styles of digital debris (i.e. debris which on the instant at the instant are not 'on-shell'). an comparable probable is going for the interactions with gravitons (the particle interpretation of the gravitational field). Photons curve around super bodies. Photons can not get away black holes whilst they are indoors the style horizon of the black holes. to boot the easy actuality that, those 2 themes are rather autonomous, different than the curvature of the photon trajectory is triggered by using the black hollow.

Answer 5

1) 1035 mph at the equator, the other are multiples of the cosine of the lattitude.
and do your own homework.


Yours:; Grumpy

Answer 6

pay attention in class. I think if people must ask these kinds of questions, then they should include the relevant coursework that was distributed or covered in class.

Answer 7

Give me the equations from your physics book, I'm way too lazy to look up mine.

Answer 8

if you need help in school then just ask don't me afraid to ask? If you need more advice just write to me at [e-mail]

Answer 9

E=MC squared....that's all I got

Answer 10

(d) I have no idea