simplify..........?

Question

2/c-3 + 5/c-2 + 13/c^2-5c+6

(2/c-3) + (5/c-2) + (13/c^2-5c+6) I think..............lol

Answer 1

(7c-6)/(c-2)(c-3)

Answer 2

Will you add in some paranthesis so I know where the equation starts and ends? I'll be back to answer this in a few hours.


Actually, never mind. I think I know where it is. This is your equation, right?: [2/(c-3)] + [5/(c-2)] + [13/(c^2-5c+6)]

If that's the equation, then it will be very easy to solve.
1. Factor anything possible
[2/(c-3)] + [5/(c-2)] + [13/(c^2-5c+6)]
[2/(c-3)] + [5/(c-2)] + [13/( )( )]
[2/(c-3)] + [5/(c-2)] + [13/(c-3)(c-2)]

2. You see that your least common denominator is (c-3)(c-2)

3. Multiply each fraction by the missing value to get your least common denominator, and that will result in the removal of fractions to make it into just one.
[2/(c-3)] + [5/(c-2)] + [13/(c^2-5c+6)]
[2(c-2) + 5(c-3) +13]/[(c-2)(c-3)]

4. Solve.
[2c-4 + 5c-15 +13]/[(c-2)(c-3)]

5. Simplify.
(7c-6)/[(c-2)(c-3)]

Answer 3

first of all use brackets if it is unclear what to evaluate...
2/c-3 = 2/(c-3) ????

2/c-3 + 5/c-2 + 13/c^2-5c+6

"Grandmums Receipt for simplifying things"
1. play with c^2-5c+6
(ratio because we are going to make the denominators equal, maybe these is some common factor in the three terms)
c^2-5c+6 = (c-3)(c-2) yesssssss !

2/(c-3) + 5/(c-2) + 13/(c^2-5c+6) =
2(c-2)/{(c-3)(c-2)} + 5(c-3)/{(c-3)(c-2)} + 13/{ (c-3)(c-2) } =

{ 2(c-2) + 5(c-3) + 13 } / (c-3)(c-2) =
(8c - 6)/ (c-3)(c-2) . (modulo errors)

Answer 4

2/(c-3) + 5/(c-2) + 13/(c^2-5c+6)

=2/(c-3) + 5/(c-2) + 13/(c - 3)(c - 2)

Find a common denominator and add together:

[2(c - 2) / (c - 3)(c - 2)] + [5(c - 3) / (c - 3)(c - 2)] + [13/(c - 3)(c - 2)]
=[2(c - 2) + 5(c - 3) + 13] / [(c - 3)(c - 2)]
=[2c - 4 + 5c - 15 + 13] / [(c - 3)(c - 2)]
=[7c - 6] / [(c - 3)(c - 2)]

=[7c - 6] / (c^2 - 5c + 6)

Answer 5

1) 2/(c-3) + 5/(c-2) + 13/(c^2-5c+6)
2) = 2(c-2)/(c-3)(c-2) + 5(c-3)/(c-3)(c-2) + 13/(c-3)(-2)
3) = (7c-6)/(c-3)(c-2)
4) = (7c-6)/(c^2-5c+6)

Answer 6

c(2/-3)+ (5/-2)+ (13/c-11)

Answer 7

I'm not so go at math but here is a site you can use that will help you with your homework on a regular basis and make sure you understand it. an onlie tutor.

Answer 8

Use A Scientific caculator