how do i solve for y?

Question

given a = -5 b =1 c=2 if y^2-a^2 = (c^2+b)^2

i think there are two solutions not just one

Answer 1

y^2 - (-5)^2 = (2^2 + 1)^2
y^2 - 25 = (4+1)^2
y^2 - 25 = 5^2
y^2 - 25 = 25
y^2 = 50
y = +/- sqrt(50)
y = +/- sqrt(25*2)
y = +/- 5sqrt(2)
Answer: y = 5sqrt(2) or y = -5sqrt(2)

Answer 2

y² - a² = (c² + b)²

Solving for y

y² - a² = (c² + b)²
+a² +a²

Add +a² to both sides of the equation

y² = √a² + (c² + b)²

Insert a = - 5, b = 1 and c = 2 values into the equation

y² = √ (-5)² + [(2)² + 1]²

y² = √25 + [4 + 1]²

y² = √ 25 + 25

y² = √50

y = 7,071067812

y = 7.07 rounded to two decimal places

Answer 3

^ = squared
given a = -5 b =1 c=2

y^2 - a^2 = (c^2+b)^2
y^2 = (c^2 + b)^2 + a^2

y^2 = (2^2 + 1) ^2+ -5^2

y^2 = 25 +25

y^2 = 50

y = squared root of 50

y = 7.07


Check the answer:
7.07^2 = (2^2 + 1)^2 + -5^2
50 = 50

Answer 4

y²-a² = (c²+b)²
y² = (c²+b)²+a² and put the values of a, b, c in this we get
y² = (2² + 1)² + 5²
y² = (4 + 1)² +25
y² = 25 + 25
y² = 50 so
y = √50
y = 7.07

Answer 5

It is so simple. Follow below.
y² = (2² + 1)² + 5²
y² = (4 + 1)² +25
y² = 25 + 25
y² = 50
y = √50
y = 7.071

Answer 6

y^2 - (-5)^2 = (2^2 + 1)^2
y^2 - (25) = (4 + 1)^2
y^2 - 25 = 5^2
y^2 - 25 = 25
y^2 = 50
y = sqrt(50)
y = sqrt(25 * 2)
y = 5sqrt(2)

Answer 7

y^2 - a^2 = (c^2 + b)^2

solve for y:

y = sqrt ((c^2 + b)^2 + a^2)

substitute values:

y = sqrt((2^2 + 1)^2 + (-5)^2)

y = sqrt((4 + 1)^2 + 25)

y = sqrt (5^2 + 25)

y = sqrt (50)

y = 7.071

Answer 8

substitute the values
simplify
y = sqrt(50)
= 7.07

Answer 9

y²-a²=(c²+b)²
y²-(-5)²=(2²+1)²
y²-(25)=(4+1)²
y²-25=(5)²
y²-25=25
y²=25+25
y²=50
y=√50
y=7.071068

Answer 10

y= sqrt(50)