president bush is one man, but he is a zero. henceforth.... it is possible to fathom that 1 = 0 at least some of the time.
2006-07-31 16:49:31
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answer #1
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answered by hellion210 6
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You can define 1 as the very first point on your number line. In this case, according to metric space theory, the distance between 0 and 1 is 0, therefore the numbers must be the same. i.e. d(x,y) = 0 iff x=y. Thus 0 = 1. Metric space theory is based on points having no extent.
2006-08-01 11:21:03
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answer #2
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answered by Anonymous
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Nobody in the world can prove 1=0. Otherwise all number shall be Zero. Is it? Whoever proves, he proves by mistake only.
2006-07-31 23:50:37
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answer #3
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answered by sharanan 2
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1 is not equal to 0.
2006-08-01 03:05:36
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answer #4
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answered by budweiser 2
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let x=1
thus, x^2 = 1 (x squared =1)
thus, x = x^2 (x = x squared)
subtract one from both sides,
x - 1 = x^2 -1
factor the right side
x - 1 = (x-1)(x+1)
divide both sides by x-1
x - 1 = (x-1)(x+1)
----- -------------
x - 1 x - 1
cancel out like factors, leaving
1 = x + 1
substitute from the original line where x = 1
1 = 1 + 1
subtract 1 from each side, leaving
0 = 1
but .... can you find the error in this?
2006-07-31 23:51:58
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answer #5
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answered by RSPKR 3
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1 never equals 0.
2006-08-01 03:21:22
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answer #6
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answered by Anonymous
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multiply zero on both the sides
1*0 = 0*0
0 = 0
L.HS = R.H.S
Hence proved
2006-08-01 04:52:11
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answer #7
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answered by Niwton 1
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1=0? 1 has a value while 0 doesnt have a value......
2006-08-01 00:24:47
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answer #8
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answered by Lycanus 2
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go to the store with 1 dollar, you'll get 0, nothing!
2006-07-31 23:48:52
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answer #9
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answered by lovinlife 3
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x^2 - y^2 = x^2 - y^2
if x = y
x (x - y) = (x+y)(x-y) (factorizing)
canceling the common factor
x = x+y
but since x=y
1 = 2
subtract one from each side
0 = 1 interposition to get
1 = 0
QED
2006-08-01 02:20:38
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answer #10
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answered by blind_chameleon 5
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