.a jeweller makes a window display. he has 7 gems of which he needs to display 6. three on the left side of the pane on three on the right. with following conditions.let the gems be Armanet, diamond, emerald , sapphire , garnet, opal and ruby.
1.armanet should be always displayed on left side
2.diamond always on the right
3.ruby should not be kept with diamond or garnet.
4.emerald and sapphire should always be on the same side.
question1]what are the possible combinations on the possible for left pane.
a] armanet,garnet , opal
b] armanet, ruby, garnet
c] diamond, emerald , sapphire
d] armanet , emerald, garnet
que2]what are the possible combinations on the possible for right pane.
a]diamond, garnet , opal
b]diamond, ruby, opal
c]armanet,emerald, sapphire
d]diamond,garnet,ruby
3]if garnet, diamond, opal are on the right side what is possible
option for right side.
a]ruby,armanet,sapphire
b]armanet,emerald,ruby
c]armanet,emerald,sapphire
d]ruby,emerald,sapphir
2006-07-31
15:52:51
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5 answers
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asked by
Anonymous
in
Science & Mathematics
➔ Mathematics