the 4/9 -3 2/3 1/4 3)2 are superscripts
2006-07-31 13:02:50 · 4 answers · asked by jbird3351 2 in Education & Reference ➔ Homework Help
It's not a trick question it's for my math class and i am stuck on it
2006-07-31 13:08:08 · update #1
(z^3y^1/4)/2y^2
You get this by multiplying all the exponents in the first parenthesis by -3 and all the exponents in the second parenthesis by 2
You then simplify the numbers, x's, y's, and z's.
Finally you get rid of any negative exponents and any fractional exponents that are in the denominator.
Post any other questions - I'll check back
2006-07-31 13:26:15 · answer #1 · answered by MollyMAM 6 · 3⤊ 0⤋
Zero
2006-07-31 13:05:26 · answer #2 · answered by Anonymous · 0⤊ 0⤋
is that a trick question.
2006-07-31 13:04:46 · answer #3 · answered by Billy Talent 3 · 0⤊ 0⤋
(32z^6)/(27y^(5/2))
I think that's right. I'll email you a walk-through so you can check it. Please check it before assuming its right!!
2006-07-31 13:22:17 · answer #4 · answered by Quiet Amusement 4 · 0⤊ 0⤋