A softball of mass 0.220 kg that is moving with a speed of 7.0 m/s collides head-on and elastically with another ball initially at rest. Afterward it is found that the incoming ball has bounced backward with a speed of 4.6 m/s. (Assume the positive direction is forward.)
(a) Calculate the velocity of the target ball after the collision (m/s)
(b) Calculate the mass of the target ball (kg)
2006-07-31 11:06:17 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Physics
Use conservation of momentum and conservation of energy. Write down the momentum and the energy in terms of the mass and speed of each ball both before and after the collision. Put in the information you know, then use algebra to get the rest. There are two unknowns (the mass and speed of the second ball after the collision) and two equations (the momentum conservation and the energy conservation) so it should all work out.
2006-07-31 11:47:21 · answer #1 · answered by Benjamin N 4 · 0⤊ 0⤋
i dont know but B
2006-07-31 11:10:47 · answer #2 · answered by Anonymous · 0⤊ 0⤋