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r ≠ ± 2, r² - 5^r + 6/r² - 4

2006-07-31 10:19:39 · 4 answers · asked by lovher206 2 in Education & Reference Homework Help

can you show the steps of how you got the answer.. The answer is no help without the break-down of how you got there. Thnx

2006-07-31 10:23:53 · update #1

4 answers

The previous two posters are joking. The answer is not 42 (that is the answer to an entirely different question). The answer is r≠±2, (r-3)/(r+2). This is done by factoring the rational expression: (r² - 5r + 6)/(r² - 4) = (r-3)(r-2)/((r-2)(r+2)). Then just cancel the r-2.

By the way, it wasn't strictly necessary to specify r≠±2 in the first expression, since obviously those values are undefined. We could have also omitted r≠2 in the final expression for the same reason (we could NOT have omitted r≠-2, however, since that would allow our solution to have a defined value where the first function does not, and that would make them different functions).

2006-07-31 10:38:47 · answer #1 · answered by Pascal 7 · 2 0

r^2-5r+6=(r-3)(r+2) and r^2-4=(r+2)(r-2)
now in (r^2-5r+6)/(r^2-4),the r+2 can be cancelled out only and only if r is not equal to -2 otherwise it will assume the 0/0 form which is indeterminate. also the r-2 in the denominator will get reduced to 0 if r=2 and reduce the expression to infinite values.
therefore only and only if r is neither 2 nor -2 this expression will be a rational expression and so it is only proper that r is not equal to plus or minus 2 is mentioned.then the rational expression can be reduced to the simplest form (r-3)/(r-2)

2006-07-31 17:45:53 · answer #2 · answered by raj 7 · 0 0

The answer is 42.

2006-07-31 10:22:31 · answer #3 · answered by Anonymous · 0 0

yes, the answer is 42.

2006-07-31 10:22:34 · answer #4 · answered by Anonymous · 0 0

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