Kygirl is right.
2006-07-31 09:49:55
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answer #1
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answered by Anonymous
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This is really easy...
60; 62; 64; 66; 68
then you just need to add the hundreds place (100...) if you need to go higher.
All you need to do is think the 6 is a 0 and count the even numbers 0; 2; 4; 6; 8.
2006-07-31 18:01:55
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answer #2
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answered by shannongood92 2
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It's obvious that the answer her teacher wants is kygirl's - that is, 60, 62, 64, 66, and 68, but willowz_tree's answer is the correct one - there are infinitely many numbers fitting those specifications, and as such your sister could not possibly list all of them (unless she uses notation such as 60+100k, 62+100k... 68+100k, where kâN; but I doubt she knows how to do that). It was careless of her teacher not to explicitly specify the restriction to two-digit numbers.
2006-07-31 17:53:57
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answer #3
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answered by Pascal 7
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60, 61, 62, 63, 64, 65, 66, 67, 68, 69, 160
and so on and so forth
2006-07-31 16:49:53
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answer #4
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answered by lostboi3008 3
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As there were 5 slots to fill I think kygirl's answer is ok, although I agree with willowz tree, there is an infinite number of them. If you want to cover them all you can do so but who pays for it for the rest of your life?
2006-07-31 17:54:36
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answer #5
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answered by Agnes K 3
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hmm.....there's a lot...how high do you have to go? there's the 60, 62, 64, 66, 68.....then theres 160 162 164 166 168.......260, 262, 264, 266, 268, etc.......and you just keep going i guess.
2006-07-31 16:48:54
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answer #6
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answered by Anonymous
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Kygirl is right. This was pretty simple, you should have tried to do it yourself. Better yet, your sister should have done it.
2006-07-31 16:49:09
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answer #7
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answered by koffee 3
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60,62,64,66,68
these are the numbers
2006-07-31 16:49:45
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answer #8
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answered by stranger 2
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good job, kygirl!
2006-07-31 16:49:23
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answer #9
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answered by peachiegirl 2
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60,62,64,66,68
2006-07-31 16:47:02
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answer #10
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answered by kygirl 2
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