chem question?

Question

In a student lab 60.0 ml of 0.700 mol/L sodium hydroxide solution was neutralized with 40.0 ml of excess sulfuric acid solution. The temperature increased by 5.6 degrees Celsius.

a) calculate the molar enthalpy of neutralization for sodium hydroxide


if posible..please provide the steps

honestly..i need this....PLZZZ :)

Answer 1

To solve for the MOLAR heat of neutralization, one needs to find the number of MOLES of Sodium Hydroxide since it is given as the limiting reactant.

It is stated that 60.0 mL of .700 M NaOH solution is neutralized.
To find the number of moles of NaOH in this solution, multiply the concentration (in Moles / Liter, AKA Molarity) by the volume (in Liters).
.700 M * .060 mL = .042 moles of NaOH.

If .042 moles of NaOH is neutralized with excess acid, in theory, all of the heat released in this reaction is due to the neutralization reaction which occurs.

To find the amount of energy released, let us assume that all of the temperature which is recorded results from the heat absorbed by the solution. We will assume that the solution has a density and specific heat equal to that of water (1 g/mL, 4.186 J/g degree C).
100 mL of solution would have a mass of 100 g and a specific heat of 4.186 J/g degree C.
Using,
Q = mC(delta T)
Q = 100 g * 4.186 J/g degree C * 5.6 degrees C
Q = 2344.16 Joules.

So if .042 moles of NaOH will release 2344.16 Joules of energy, how much would 1 mole release?
2344.16 J / .042 moles = 55813.3 Joules / 1 mole.
So the molar heat of neutralization would be 55813.3 J/mol.

* We did make some key assumptions as to the solution's density and specific heat.

** I do not like the question's procedure as it is phrased. If excess sulfuric acid is added to neutralize the solution, then there must be some left over in the end. Everyone knows that diluting sulfuric acid is an exothermic process.....it will release heat. This extra heat released by the dilution of the H2SO4 will also raise the temperature of the final solution.
The proper way to do this would be to perfectly neutralize the solution, one should not have any extra acid left over since that will interfere with the calculations needed to find the heat released during the reaction we are concerned with.

Answer 2

a million.0 Potassium is amazingly electropositive ingredient with low ionization skill. This sources makes the outer valance electrons ejection really uncomplicated with electric powered voltage. As you recognize electric powered impulses are through flow of electrons 2.0 4 moles of Al reacts with 3 moles O2 giving Aluminum oxide. this signifies that 8 moles of Al choose six moles of O2 3.0 crew III era iv, probable the ingredient is Ga and the Oxide is Ga2O3 4.0 1s2 2s2 2p6 3s13Px1

Answer 3

stop asking me to do your homework

Answer 4

do ur homework urself

Answer 5

60ml(.700M)=40.0ml(M)

42.0mol=40.0ml(M)

42.0mol/40.0ml=M

=1.05M