log 3^x equals xlog 3
so
x log3 - 4log 3 = 12log3
x-4=12
x=16
2006-07-31 04:43:02
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answer #1
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answered by sunil 3
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When dealing with logarithms, here is the property you need:
When numbers are raised to exponents within the logarithmic function, the exponent can be treated as a multiplicative coefficient in front of the log function.
Here is a rewrite of your problem:
xlog3-4log3=12log3
X=16
Logarithmic functions were quite popular for engineering applications in the days of the slide-rule because they changed difficult mathematical operations into additions and subtractions.
2006-07-31 04:46:53
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answer #2
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answered by El Gringo 237 3
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log(3^x/3^4)=log3^12
=3^(x-4)=3^12;
x-4=12;
x=16 ans
2006-07-31 06:35:18
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answer #3
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answered by Gunjit M 2
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xlog3-4log3=12log3 ==> (x/4)log3=12log3 ==> x/4 = 12 ==> x=48
X = 48
2006-07-31 07:34:32
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answer #4
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answered by Lizel B 2
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log(3)x - log(3)4 = log(3)12
log(3)(x/4) = log(3)12
(x/4) = 12
x = 48
ANS : 48
2006-07-31 10:43:02
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answer #5
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answered by Sherman81 6
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good question gosh
2006-07-31 04:43:09
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answer #6
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answered by ♥blah♥ 3
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