thats is how its written in the paper i need help plz
2006-07-31 04:34:49 · 8 answers · asked by ashka e 1 in Science & Mathematics ➔ Mathematics
is this the complete equation? I think it lacks = !!!
Is it like (x+2)/(x-5)+6=0?
2006-07-31 04:41:10 · answer #1 · answered by Massomeh 2 · 0⤊ 0⤋
If this is exactly how it is written then you work it kind of like a mixed number trying to get it as an improper fraction. So you change 6 to 6(x-5)/(x-5) That gives you a numerator of x+2+6(x-5) which simplifies to 7x -28 and put that over a denominator of x-5. So the anser is (7x-28)/(x-5)
2006-07-31 12:40:04 · answer #2 · answered by MollyMAM 6 · 0⤊ 0⤋
(x + 2)/(x - 5) + 6 = 0
Move the +6 to the right and change the sign,
(x + 2)/(x - 5) = -6
Multiply both sides by x-5,
x + 2 = -6 (x - 5)
x + 2 = -6x + 30
x + 6x = 30 - 2 (just moved the -6x to the left and +2 to the right and changed the signs)
7x = 28
x = 28/7
x = 4
2006-08-01 01:13:02 · answer #3 · answered by Anonymous · 0⤊ 0⤋
16
2006-07-31 11:43:29 · answer #4 · answered by none 5 · 0⤊ 0⤋
(x+2)/(x-5)+6 = 7(x-4)/(x-5)
2006-07-31 11:42:09 · answer #5 · answered by Martha D 1 · 0⤊ 0⤋
multiply n divide 6 by (x-5) n then take 1/(x-5) common...
so u get:
= ((x+2) + 6(x-5))/(x-5)
= (x+2 + 6x -30)/(x-5)
= (7x -24) / (x-5)
now u can leave the answer like this...or actually go about dividing 7x-24 with x-5
2006-07-31 13:32:30 · answer #6 · answered by luv_hanoz 2 · 0⤊ 0⤋
(x+2)/(x-5) + 6 = 0, x must be different than 0
((x+2) + 6(x-5))/(x-5) = 0
(x + 2 + 6x - 30)/(x-5) = 0
(7x - 28)/(x-5) = 0
x cannot be 0, so
7x - 28 = 0
7x = 28
x = 28/7 = 4
2006-07-31 11:44:03 · answer #7 · answered by biliana 1 · 0⤊ 0⤋
x can be any real number except 5, which would cause the ratio to be undefined.
2006-07-31 11:38:12 · answer #8 · answered by jimvalentinojr 6 · 0⤊ 0⤋