well the best way to approach this is to ln both sides:
ln 104^t = ln 2
t ln 104 = ln 2
t = ln2/ln104
t = 0.1492
2006-07-30 18:15:17
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answer #1
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answered by jaredkomahalko 2
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Let x=104 and t=2
so x raise power t or x^t = 104^2 or 104 * 104 = 10816
is the correct answer.
2006-07-31 02:56:01
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answer #2
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answered by Ðøwñ tø Ëã®th 5
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104^t = 2
Take log base 104 on both sides
t = log base 104 of 2
t is about 0.149244
2006-07-31 01:16:59
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answer #3
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answered by Michael M 6
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taking logarithm on both sides,
log 104^t = log 2
t log 104 =log 2
t=log 2 / log 104
t=0.149
2006-07-31 01:17:11
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answer #4
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answered by sunil 3
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ln104^t = ln 2
t ln 104 = ln 2
t = ln2/ln104
t = 0.149244
2006-07-31 01:33:15
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answer #5
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answered by sharanan 2
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log 2 (base104)=t
log 2/log 104=t
use your calculator.
2006-07-31 01:14:57
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answer #6
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answered by Anonymous
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In general, the solution for an equation like:
a^x=b
is:
x = ln(b)/ln(a)
given that b > 0.
For your case, the solution is:
t = .14924
2006-07-31 01:19:08
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answer #7
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answered by otac0n 1
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log(104^t)=log2
t*log(104)=log2
t=log(2)/log(104)
t=0.149
2006-07-31 01:28:43
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answer #8
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answered by female_lizzzzzard 3
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t*log104=log 2
t=2.01703333/0.3010299
t=6.7
2006-07-31 01:35:07
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answer #9
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answered by sanjeewa 4
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