Answer this maths problem!?

Question

How to prove in writing only that Area of a triangle is half its base times height.? Please show calculation. Thanks.

Answer 1

if a parallelogram and a triangle are on the same base and between the same parallels the area of the triangle is half the area of the parallelogram and the area of the parallelogram is b*h
therefore the area of the triangle is (1/2)(b*h)

Answer 2

Very simple.
Draw a square (equal sides)
Cut it across the diagonal and you get 2 equal triangle.
And you know the thoery that since the square is cut by two there for the area is half that of the square.

Therefore the area is 1/2 x (area of square)
And since the area of square is length X breadth ( or base x height)

Therefore it is proven that area of triangleis 1/2 x base x height.

Answer 3

1. Area = a*h/2

h is the height of the altitude of the triangle with base a.

The big rectangle is made up of two smaller rectangles with areas d*h and e*h. So the big triangle is made up of two smaller right-angled triangles whose areas are half of the smaller rectangles, i.e. d*h/2 and e*h/2. But a=d+e so the area of the large triangle is d*h/2+e*h/2 = a*h/2.

If one of the angles on the base is obtuse then the proof involves subtracting one half-rectangle from another.

Answer 4

area of triangle=i/2 [base*height]
perimeter=L+B+H
AREA OF REQUIRED TRIANGLE= AREA BOUNDED BY THE PERIMETER - AREA UNDER THE THREE SIDES.
THEREFORE, A=1/2 [B*H]

Answer 5

use the 30-60-90- theorem

Answer 6

Look it up on the Internet. You will find the answer.

Answer 7

http://aleph0.clarku.edu/~djoyce/java/trig/area.html

check out the flash in it...
cant paste it here..

Answer 8

I love
Wikipedia.org
You should use it.