The general equation of a straight line is:
y = mx + c
Where m is the gradient and c is the y-intercept.
For the given line,
y = 2x + 6
Let the gradient m1 = 2.
Let the equation of the perpendicular line be,
y = m2 x + c
Where two lines are perpendicular, the following is true,
m1 m2 = -1
Therefore
(2) m2 = -1
m2 = -1/2
Hence the equation of the perpendicular line is,
y = -1/2 x + 3
2006-07-30 18:25:30
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answer #1
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answered by ideaquest 7
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y=2x-9 or y=2x+-9 The slope is m and the y-intercept is the place the line crosses on the y axis or in an ordered pair the selection it quite is interior the y place (x,y) if the x is a nil. Y and x the two stand for coordinates in an ordered pair ( to boot the single listed on account which you already used y).
2016-12-11 03:19:38
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answer #2
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answered by ? 4
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Perpendicular lines have slopes that are negative reciprocals of one another. The given line has slope = 2, so the perpendicular line must have slope = -1/2
y = (-1/2)x + 3
2006-07-30 17:28:16
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answer #3
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answered by jimbob 6
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y=1/2x+3
since any line whcih has a slope reciprocal to a given line is perpendicular to that given line... the reciprocal of 2 is 1/2...
2006-07-30 17:22:36
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answer #4
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answered by angel r 2
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i will answer all of your questions here
the only equation needed is y=Mx+B
y intercept is a point (0,b)
for a given slope M the perpendicular slope MP is found by solving (M)*(MP)=-1 for MP
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general procedure is first write equation with value of M (or MP for perp. line) in leaving the B as "B" then find a point on line say (point is found from information given) say (x1,y1) substitute into above equation and only the "B" reamins which we solve for as usual
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IF YOU ARE GIVEN YOU NEED STEPS
slope M & y int. B eq. of perpendicular line 1. solve M*MP=-1 for MP
2. use (0,B) for (x1,y1)
3. m=MP,x=x1,y=y1 solve
for B
equation & point " " 1. rewrite into y=Mx+B form
2. solve M*MP=-1 for MP
3. same as 3. above
2 points " " 1. find slope M=(y2-y1)/(x2-x1)
2. same as 2. above
3. same as 3 above
the general procedure above is fastest way to produce linear equations from given info
the table is merely a demonstrative example of this procedure
ENJOY
2006-07-30 18:07:50
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answer #5
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answered by ivblackward 5
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y=3-x/2...
2006-07-30 17:32:22
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answer #6
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answered by Second Newton... 2
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y=-1/2x+3
2006-07-30 17:19:56
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answer #7
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answered by Michael M 6
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