by experiment it has been found that 2.18 g of zinc metal combines with oxygen to yield 2.71 g of zinc oxide. how many grams of oxygen reacted with zinc metal?
explaination is appreciated =)
2006-07-30 15:38:13 · 5 answers · asked by asperity 2 in Science & Mathematics ➔ Chemistry
I could be wrong because I don't want to think too hard but it should be .53 grams of oxygen because the mass is not created or destroyed. 2.71 g ZnO - 2.18 g Zn
2006-07-30 15:42:47 · answer #1 · answered by Jake S 5 · 4⤊ 0⤋
Look at the question, there is no chemistry needed.
If you have 2.18 grams of zinc and 'x' grams of oxygen to make 2.71 grams ZnO, then simply subtract 2.18 g zinc from the total 2.71 to find out how much oxygen is used, i.e., 2.71 - 2.18 = 0.53 grams oxygen.
That seems to easy. I'm not sure of this one.
2006-07-30 22:57:38 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Here are the steps:
1. Figure the empirical chemical equation for oxygen and zinc reacting to form zinc oxide.
2. Divide the mass of the zinc metal by the atomic mass of zinc and its empirical number
3. Do the same for for zinc oxide.
4. Multiply both numbers by the 2 times the atomic mass and empirical number of oxygen.
5. Both numbers should match and equal the grams of oxygen.
2006-07-30 22:46:50 · answer #3 · answered by AldericII 2 · 0⤊ 0⤋
0.53 g. The reaction combines oxygen with zinc, and everything stays put in the form of zinc oxyde. So the final mass is the sum of both reactants, that of the initial zinc, and that of the oxygen. A simple substraction gives you what the oxygen amounts to.
2006-07-30 22:43:50 · answer #4 · answered by Vincent G 7 · 0⤊ 0⤋
i believe it would be 2.18 g due to the fact that matter is neither created or destroyed
2006-07-30 23:29:28 · answer #5 · answered by ureverydayfetish 2 · 0⤊ 0⤋