2006-07-30 14:27:24 · 6 answers · asked by Scott R 6 in Science & Mathematics ➔ Mathematics
Prove it please.
2006-07-30 14:36:19 · update #1
1+1+2+4 = 1*1*2*4
2006-07-30 14:48:55 · update #2
NOTE TO: alnitaka
a(x), 0≤x≤n, can be any non-negative integer, it is not a function.
2006-07-30 14:59:29 · update #3
that last note should have read 1≤x≤n ! sorry.
2006-07-30 15:00:48 · update #4
Note that B + C + d(1) + d(2) + ... + d(BC - B - C) = B * C * d(1) * d(2) * ... * d(BC - B - C)
where d(n) = 1 for all n
2006-07-30 15:13:31 · update #5
This is an interesting number theoretical problem. I suspect the answer to this question will not come very easily, and probably not from Yahoo! Answers.
An observation is that, for all natural numbers n>=2, 1+1+...+1+2+n = 1*1*...*1*2*n, where the number of 1s is n-2.
This gives:
2+2 = 2*2
1+2+3 = 1*2*3
1+1+2+4 = 1*1*2*4
1+1+1+2+5 = 1*1*1*2*5
and so on.
Hence there is at least one solution for all n.
2006-07-30 17:49:29 · answer #1 · answered by Anonymous · 2⤊ 1⤋
2+2=2*2
1*2*3=1+2+3
2006-07-30 21:46:51 · answer #2 · answered by mathematician 7 · 0⤊ 0⤋
Define the function a. Then maybe the problem can be solved.
2006-07-30 21:54:25 · answer #3 · answered by alnitaka 4 · 0⤊ 0⤋
is this what you are asking about (the theorems at the middle of the page)
http://www.marmet.ca/louis/sumprod/index.html
2006-07-30 23:03:17 · answer #4 · answered by qwert 5 · 0⤊ 0⤋
All zeros works, too.
2006-07-30 23:04:40 · answer #5 · answered by Benjamin N 4 · 0⤊ 0⤋
GOD I HATE ALEGABRA~!
2006-07-30 21:32:19 · answer #6 · answered by Scott C 2 · 0⤊ 0⤋