What does this mean? Parse error: parse error, expecting `','' or `';'' in /path/... on line 50

Question

I have been racking my brain and searching for answers all f@*%'in day! Working with PHP 4.1.2 and MySQL 3.23.53 using Dreamweaver 8

Here is my code:

define('DBLOGIN_ID', 'db020024063');
define('DBPASSWORD', '20024063');
define('DBHOST', 'localhost');
define('DBNAME', 'db020024063');
$DBconn = mysql_connect(DBHOST, DBLOGIN_ID, DBPASSWORD);
$DBselect = mysql_select_db(DBNAME, $DBconn);
$runquery = "SELECT * FROM tbl_employees";
$result = mysql_query($runquery, $DBconn) or die("

Unable to execute the query.

"
. "

Error code: " . mysql_errno()
. "Error: " . mysql_error() . "

");
$row = mysql_fetch_assoc($result);

do {

// here is line 50:

echo " . " " . $row['lname'] . . " " . View . "

";


} while ($row = mysql_fetch_assoc($result));
?>

Answer 1

It must be an error in your concatenation. Unfortunately, Yahoo! chops off most of your code, but feel free to contact me if you need help.

I am afraid I could not reply as your email address does not appear to be confirmed. However, here is my reply:

==========================================
Indeed, the error is in that line. You quotes are conflicting with each other and sometimes missing altogether. Try this:

echo ''
. $row['lname'] . '

View

Answer 2

First off, the quotes for link( the a href) need to be escaped. It should be


and anywhere else like this. This is because the PHP will see the quotes as ending the quote. If you need the quote in normal html, it needs to be escaped if it is in a php echo.

See if this helps. You may want to post line 49, PHP errors aren't always on the line that the parser says they are on.

Plus Yahoo! is messing up displaying the code because it is trying to show the link as an html link.