a)What is the momentum of a 27.0 g sparrow flying with a speed of 13 m/s?
(b) What will be its momentum 12 s later if a constant 2.0 10-2N force due to air resistance acts on it?
i got part a..i'm looking for part b..thanks for your help
2006-07-30 09:47:18 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Physics
it's 2.0*10^(-2)
2006-07-30 09:54:51 · update #1
(a) mv(t1)=(27/1000 kg)(13m/s)=0.351 kg m/sec
(b)The computations are secondary to an important concept expressed by Newton who did not really said F=m * a.
What he really said was F= (change in momentum)
F=(mv(t2)-mv(t1))/(t2-t1)=
Finally it is well known as
F=m(v(t2)-v(t1))/(t2-t1)
m(v(t2)-v(t1))=F(t2-t1)
m v(t2) = F(t2-t1) +mv(t1)=
=2.0 *10^-2N(12s)+(27/1000 kg)(13m/s)=
=0.240+0.351=0.591 kg m/sec
2006-08-02 15:21:08 · answer #1 · answered by Edward 7 · 1⤊ 0⤋
P = mv. Linear momentum = mass * velocity.
F = P - P0 / (t - t0).
Force equals final momentum minus initial momentum over time.
2006-07-30 09:52:29 · answer #2 · answered by the redcuber 6 · 0⤊ 0⤋
ÎP = F * t
That ought to let you solve it yourself.
2006-07-30 09:52:22 · answer #3 · answered by Engineer-Poet 7 · 0⤊ 0⤋