A cylinder has a diameter of 15 cm. The water level in the cylinder is maintained at a height of 0.45 m. If the diameter of the spout pipe is 0.50 cm, how high is h, the vertical stream of water? (Assume the water to be an ideal fluid.)
2006-07-30 06:37:35 · 7 answers · asked by jamey.moore@sbcglobal.net 1 in Science & Mathematics ➔ Physics
The problem has to do with "Bernoulli's principle." Why: as water is added to the cylinder, the level stays the same, so all of the water already inside the cylinder must be moving. Since the water is incompressible, the volume through the cylinder and the volume through the spout have to be the same. But the spout has a smaller diameter--so the water coming out has to have been accelerated. What force causes that acceleration? The pressure difference between the bottom of the water column and the atmosphere.
The problem has to do with the conservation of energy: water is being dropped in one end, and spouted to a certain height at the other. Certainly the height attained depends on the speed with which the water exits the cylinder. This might have to do with how the water in the cylinder is falling.
General hints to gain insight into the problem: see what equations you can get from the facts that the amount of water leaving=the amount of water entering and that energy is at all instants conserved. Split the situation into parts: water is added, water level drops, net result=no change.
2006-07-30 07:00:10 · answer #1 · answered by Benjamin N 4 · 3⤊ 2⤋
0.45 m from the bottom of the cylinder, if the spout is angled so as to allow the fluid to go up vertically, that is.
The pressure of the head of water pushes the water up to a level that is the same as the surface of the cylinder. The diameters of the cylinder and that of the spout have no influence if the fluid is considered ideal (non viscous).
2006-07-30 06:48:15 · answer #2 · answered by Vincent G 7 · 0⤊ 0⤋
I think you need to specify the location of the spout, don't you? The lower on the cylinder it is, the higher the water pressure.
2006-07-30 06:42:38 · answer #3 · answered by retiredslashescaped1 5 · 0⤊ 0⤋
You are going to need to give more detail about the spout. Is it horizontal or angled? Are you talking about the zenith of the water?
2006-07-30 06:42:32 · answer #4 · answered by DoctaB01 2 · 0⤊ 0⤋
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2016-10-01 06:35:00 · answer #5 · answered by Anonymous · 0⤊ 0⤋
just point with your right arm.
then if you want to go in the left direction go where your left arm points.
2006-07-30 06:40:40 · answer #6 · answered by t10t200 2 · 0⤊ 0⤋
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2006-07-30 06:41:21 · answer #7 · answered by el.tuco 5 · 0⤊ 0⤋