Ok i got this problem in a book but cant solve, can any one help ?
If
a^2 = b^3 = c^5 = d^6
Prove that
log of abc to the base (d) = 31/5
2006-07-29 21:21:30 · 4 answers · asked by Worst 2 in Science & Mathematics ➔ Mathematics
Simple!
Just rearrange for a, then b, then c in terms of d.
For example, a^2 = d^6 so a = d^3
b^3 = d^6 so b = d^2
c^5 = d^6 so c = d^(6/5)
so abc is simply d^3 * d^2 * d^(6/5)
= d^(3 + 2 + 6/5)
= d^(31/5)
Hence log to the base d of d^(31/5) = 31/5
Thus shown.
Hope this helps!
2006-07-29 21:28:09 · answer #1 · answered by ? 3 · 3⤊ 0⤋
It is simple:convert the number to the base (d)
if a^2=b^3=c^5=d^6 then
a=d^3
b=d^2
c=d^(6/5)
therefore abc=d^(3+2+6/5)=d^(31/5)
and thus;
log (abc) to the base d = 31/5
2006-07-30 04:33:20 · answer #2 · answered by skahmad 4 · 0⤊ 0⤋
Won't a graphing calculator figure that out for you? Buy a TI-84 and let it do all the dirty work.
2006-07-30 04:26:58 · answer #3 · answered by yumyum 6 · 0⤊ 0⤋
Jamesrobin your a answer will be selected the best,
thanx mate,
[ i am the asker in a different id ]
2006-07-30 04:30:21 · answer #4 · answered by wp1_wp1 1 · 0⤊ 0⤋