a ring with a mass of 368grams if drop in the initial volume of water which is 48ml if the water rose at 68ml ifthe ring is dropped in the water?
2006-07-29 20:42:39 · 9 answers · asked by _heart me♥ 1 in Science & Mathematics ➔ Mathematics
density = mass / volume
368grams / ( 68ml - 48ml) = 368 g / 20 cm3 = 18 g/cm3 =
18 kg/dm3 = 18 ton/m3
Th
2006-07-30 00:09:16 · answer #1 · answered by Thermo 6 · 0⤊ 0⤋
368 grams
Volume of ring = difference in water levels
= 68ml - 48ml = 20 ml
Density = mass/ volume = 368g/20ml = 18.4 g/ml
2006-07-30 21:45:05 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Mass of ring = 368g.
Volume or ring = volume of displaced water = 68ml - 48ml = 20ml.
Density = mass / volume.
Density = 368g / 20ml 18.4g/ml = 18.4Kg / L.
2006-07-30 03:54:01 · answer #3 · answered by Brenmore 5 · 0⤊ 0⤋
If one can assume the ring then has a volume of 20 mL or the total displacement of the water, and density =mass/volume, then density of the ring = 368g/20mL . 1mL =1 cm^3. 368/20=18.4
so, I would guess the density is 18.4g/cm^3
2006-07-30 03:54:47 · answer #4 · answered by quntmphys238 6 · 0⤊ 0⤋
You know that the ring is 20 ml in volume because it displaced 20 ml of water.
Density = Mass / Volume
Density = 368 g / 20 ml = 18.4 g per ml. I don't know what units you need the answer in.
2006-07-30 03:47:24 · answer #5 · answered by Michael M 6 · 0⤊ 0⤋
The volume of the object would be 20. by the density equation, m/V, you will get.18.4 g/cm^3.
2006-07-30 03:47:38 · answer #6 · answered by hkl 3 · 0⤊ 0⤋
Previous responders have the right idea, although the second one made an error in arithmetic. The substance could be an alloy of gold -- it is dense enough, but not quite dense enough to be pure gold.
2006-07-30 03:50:30 · answer #7 · answered by Anonymous · 0⤊ 0⤋
Density = Mass / Volume . do the math
2006-07-30 03:49:47 · answer #8 · answered by two_cents 1 · 0⤊ 0⤋
d=m/v
d=368/20ml(or cm^3)
d=18.4g/ml or 18.4 g/cm^3
2006-07-30 09:33:21 · answer #9 · answered by Croasis 3 · 0⤊ 0⤋