The area of a trapezoid is equal to half of the product of the height and the sum of the bases.wats 1 base?

Question

the area of a trapezoid is equal to half of the peoduct of the height and sum of the bases. rewrite the expression isolating one of the bases

Answer 1

A = (1/2) h (a + b) = h(a + b)/2 where a & b are the two bases.

All you have todo is solve for either a or b:

a + b = 2A/h

a = 2A/h - b

That's one answer. You can also have a & b trade places. That would be the other answer.

Answer 2

The bases are the parallel sides. You can think of this as taking the average of the two bases and multiplying by the height (the distance between the two bases.) Rearrange the equation so that instead of

Area = 1/2(Height)(base1 + base2)

we write

Area = Height(base1 + base2)/2

Effectively what we are doing is finding the area of a rectangle whose area is equivalent to that of the trapezoid.

While it is theoretically possible to divide the trapezoid into two triangles and a rectangle, unless you know the angles or sides of the triangles, you can't find their area. So this way is easiest.

Answer 3

The bases are the two parallel sides. It does not matter which one is base 1 or base 2.
Area = 1/2 * h * (b1 + b2).
You want to isolate the b1 to rewrite the expression.
To rewrite, multiply everything by 2.
2 * Area = h * (b1 + b2)
Next, divide both sides by h.
(2 * Area) / h = (b1 + b2)
Finally, subtract b2 from both sides.
(2 * Area) / h - b2 = b1
There ya go!

Answer 4

just divide the trapezoid into two triangles and a rectangle . the earea for a triangle is 1/2b.h and the rectangle is b.h

Answer 5

Base sides are the side parallel to each other

Answer 6

bases are the lines that are parallel to each other

Answer 7

Area = h(a + c)/2

A = h(a + c)/2
2A = h(a + c)
(2A)/h = a + c
a = ((2A)/h) - c