Solve: 4/x² - 2x- 3 = [-x/x-3] [-1/x+1]
2006-07-29 09:57:46 · 4 answers · asked by sabrina s 2 in Science & Mathematics ➔ Mathematics
The first thing I notice here is that if you multiply the two denominators on the right you get the denominator on the left. So I clear those fractions by multiplying both sides of the equation by (x-3)(x+1). You don't have a + or - in between those brackets so I'm going to assume this is a multiplication problem on the right side.That gives you:
4= -x(-1) or x = 4
2006-07-29 10:41:13 · answer #1 · answered by MollyMAM 6 · 0⤊ 0⤋
hmmm
I get a different answer to Moll...
I interpret it as
4/(x² - 2x- 3) = (-x/(x-3)) (-1(x+1))
and I get a nasty cubic which comes down to x(x² - 3x +5) = 0
Which comes out as x = 0 or 3/2 +/- i SQR(11)/2
But this seems unnecessarily complicated. I don't think Sabrina is doing complex numbers yet
the trouble is... I initially thought it was
(4/x²) - 2x- 3 = [-x/(x-3)] [-1/(x+1)]
which gives me a DIFFERENT set of answers! :(
2006-08-01 07:59:53 · answer #2 · answered by Orinoco 7 · 0⤊ 0⤋
Perhaps this site will help you:
http://algebrahelp.com/calculators/equation/
2006-07-29 17:06:55 · answer #3 · answered by susan999 3 · 0⤊ 0⤋
try doing it yourself first plz or you won't learn
2006-07-29 17:02:09 · answer #4 · answered by hpanna47 2 · 0⤊ 0⤋